1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
<h2>
Explanation:</h2>
Let's use a trial and improvement method to find this solution.
Step 1. Let's choose x = 8.5
Substituting into the equation:

Step 2. Let's choose x = 8.4
Substituting into the equation:

Step 3. Let's choose x = 8.3
Substituting into the equation:

Since the sign of the equation changes from positive to negative when evaluating from 8.4 to 8.3, then x = 8.3 seems to be a reasonable value. Finally, the solution to 1 decimal place is:
Here, Coordinates: (4, 5) & (8, 9)
Calculation of Slope, m = y2-y1 / x2-x1
m = 9-5 / 8-4
m = 4 / 4
m = 1
Now, Take any coordinate:
y - y1 = m(x - x1)
y - 5 = 1(x - 4)
y - 5 = x - 4
y = x + 1
In short, Your Answer would be: y = x + 1
Hope this helps!
H < 1 I think that's the answer