Answer:
F = 124 N
Explanation:
Given that,
The mass of bicycle and the rider, m = 12 kg + 50 kg = 62 kg
Acceleration of system, a = 2 m/s²
We need to find the force required to accelerate the system. We know that,
Net force, F = ma
Put all the values,
F = 62 kg × 2 m/s²
F = 124 N
So, the required force is equal to 124 N.
Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:
180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s
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Answer:
Part a)
Part b)
Part C)
Part d)
Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.
Explanation:
Part a)
As we know that car A moves by distance 6.1 m after collision under the frictional force
so the deceleration due to friction is given as
now we will have
Part b)
Similarly for car B the distance of stop is given as 4.4 m
so we will have
Part C)
By momentum conservation we will have
Part d)
Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.