1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kirill [66]
3 years ago
12

Subtract -2x-10 from 10x^2+3

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer: 10x^2​​+13+2x

Step-by-step explanation:

10x^2+3 - (-2x-10)

10x^2+3+2x+10

Collect like terms and simplify

10x^2+(3+10)+2x

10x^2​​+13+2x

You might be interested in
At an end- of-season sale, a kid's pool was on sale for $168 . A sign advertised that this was 20% off the original price. What
Bogdan [553]

Answer: $134.40

Step-by-step explanation: Just find 80% of 168. That is because 100 - 20 is 80. The question says 20% OFF.

7 0
3 years ago
Read 2 more answers
9. A skydiver jumps from a plane at
Neko [114]

Step-by-step explanation:

write the one digit in the square of each of the following numbers

a.13

6 0
3 years ago
Something for which someone is responsible and it "takes money out of the pocket" is called a/an
DiKsa [7]

Answer:

luydf;viu;idsgf;dvvoihsVO'IIHHO'IF'SOIGIHWR'GHW'OOFH'OIRWG'ISKAJG'IVVGFUVDHHBOISHVPIhIHUEFUEFJUSB

Step-by-step explanation:

I JUST NEED POINTS

8 0
3 years ago
Can someone help me with this? PLs i'm so confused!
barxatty [35]
1. E. sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

2. L. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

3. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}

4. Y. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

5. W. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

6. tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}

7. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

8. W. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}

9. I. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

10. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

11. E. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}

12. I. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

13. U. sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}

14. I. cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}

15. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}

16. R. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}

17. M. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}

18. N. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}

19. L. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}

20. H. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}

21. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}

22. O. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

23. O. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

24. N. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1
7 0
3 years ago
PLEASE HELP URGENTLY!!
Yuri [45]

Answer:

TPW is a isosceles because it has at least two equal sides and two equal angles (two congruent sides and angles)

Step-by-step explanation:

Hope that helps dude !

8 0
3 years ago
Other questions:
  • Daniel needs to sell candy bars For a club fundraiser. She starts with 72 candy bars and begin selling at a constant rate of eig
    9·1 answer
  • Bella has 4 packs of spikes and 8 Beetlebots. The spikes come in packs
    6·1 answer
  • Please help me or i will fail
    13·1 answer
  • Three consecutive integers have a sum of 168. What is the value of the largest integer
    12·1 answer
  • Circle G:(x-14)^2+(y+12)^2=49 and Circle H:(x-18)^2+(y-8)^2=196. Describe a complete series of transformation from Circle G to C
    13·2 answers
  • $5000 dollars is borrowed for 3 months at an annual interest rate of 18%. How much interest must be paid?
    14·1 answer
  • The letter S is made by connecting points A,B,C,D,E, and F. A scaled copy is made using points T,U,V,W, X, and Y х Z V w E F D С
    13·1 answer
  • Which lines are parallel to 8x + 4y = 5? Select all that apply.
    10·2 answers
  • Will give brainliest answer
    7·1 answer
  • Chose all that are true of the quadratic function f(x) in standard form
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!