In order to find the equation of the line, you must first find the gradient of the line
Gradient of a line (m)= (y2-y1)/(x2-x1) .....Now you substitute the points... = ((-1)-4)/(7-(-3)) = (-5)/(10) = -1/2
Therefore the gradient is negative a half (-1/2)
Now we can find the equation of the line. You can use one of the two points to find the equation of the line
Equation of a line: y-y1=m(x-x1) ... I chose to use (7,-1) as my points.... y-(-1)=-1/2(x-7) y+1=-x/2+7/2 y=-x/2+(7/2)-1 1) y=-x/2+5/2 ..... if you would like you can multiply everything by 2 to have while numbers instead of fractions .... 2) 2y=-x+5 ... if you are uncomfortable of having x as negative, you can transpose it carrying both the -x and the 5 to the side of the 2y. NOTE that the sign changes and the equation will be equal to 0.... 3) 2y+x-5=0
1,2 and 3 are all correct answers, just in different forms
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