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natka813 [3]
3 years ago
8

Write the nature of roots of the quadratic equation 9x^2 -6x+2

Mathematics
1 answer:
QveST [7]3 years ago
7 0

Answer:

roots are not real

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 (a ≠ 0 )

Then the nature of the roots can be found using the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real and distinct

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 then roots are not real

Given

9x² - 6x + 2 = 0

with a = 9, b = - 6, c = 2 , then

b² - 4ac = (- 6)² - (4× 9 × 2) = 36 - 72 = - 36

Since b² - 4ac < 0 then the roots are not real

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Volgvan

This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent  ' sin(2x) ' .
Here we go:

Original equation:                Q² - 0.5 Q  =  0

Factor the left side:            Q (Q - 0.5)  =  0

This equation is true if either factor is zero:


--  If  Q=0, then  sin(2x) = 0

                                 2x = 0°,  180°,  360°

                                   x = 0°,  90°,  180°


-- If  (Q-0.5) = 0, then      Q  =  0.5

                                sin(2x)  =  0.5          

                                       2x  =  30°,  150°

                                         x  =  15°,  75°


The whole collection of solutions
between  0°  and  360° :

          x = 0°,  15°,  75°,  90°,  180° .

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Answer:

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Stp/lanation:

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Answer:

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Step-by-step explanation:

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Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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