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podryga [215]
3 years ago
5

A movie theater sells tickets to a new show for $11 each. The theater also sells small containers of popcorn for $5 each. The th

eater needs to make $3062 in order to break even on the show.
Enter a linear equation that describes the problem.

An equation for the amount of money earned by the movie theater is
= $3062, where t is the number of tickets sold, and p is the number of popcorn buckets sold.
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

Step-by-step explanation:

An equation for the amount of money earned by the movie theater is

= $3062, where t is the number of tickets sold, and p is the number of popcorn buckets sold.

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strojnjashka [21]

Answer: 2x-1/4

Step-by-step explanation: Simplify the expression.

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Estimate 3 2/5 to the nearest integer
pickupchik [31]

4 is the nearest integer

as a decimal this number would be 3.5, which would round up to 4.

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2 years ago
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
2 years ago
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Alekssandra [29.7K]

Answer:

y = 6.50x + 6 or 71 = 6.50x + 6

10 people are the max you can invite

Step-by-step explanation:

We have the simple equation

y = 6.50x + 6

6.50x because it it per person

6 because it is a flat one time charge

We want the max to be 71 so that will be our y

71 = 6.50x + 6

We are now going to solve for x

65 = 6.5x

x = 10

Hope it helps! (:

4 0
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