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insens350 [35]
3 years ago
5

What is the value of the expresion?

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer: D

Step-by-step explanation:

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Starting with x=4.62 repeating express x as a fraction in simplest form
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x=4.62=4+0.62=4+\dfrac{62}{100}=4+\dfrac{62:2}{100:2}=4+\dfrac{31}{50}\\\\\text{as a mixed number}\ 4\dfrac{31}{50}\\\\\text{as an improper fraction}\ \dfrac{4\cdot50+31}{50}=\dfrac{231}{50}

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An isoceles triangle measures 30°. which other angles could be on that isoceles triangle​
hoa [83]

Answer: 75 degrees on the other two angles because all of the angles added together should be 180. So if you do 180-30 then divide that by 2 you get the other two angles.

Step-by-step explanation:

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Nishi practiced violin for 3 1/2 hours in a 5-day period. How many minutes
Kitty [74]

Answer:

.7 min per day

Step-by-step explanation:

3.5 ÷5=0.7

0.7×5=3.5 or 3 1/2

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Sofia's poster is 0.75 meter long. Rafael's poster is 0.35 meter less than 1 meter long. Which expression shows the difference i
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0.75 - (1-0.35) or 0.75 - 1 + 0.35
5 0
3 years ago
The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

7 0
3 years ago
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