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3 years ago

What is the value of the expresion?

Mathematics

1 answer:

Sedbober [7]3 years ago

8 0

Answer: D

Step-by-step explanation:

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Rudik [331]

Answer: what grade is this

Step-by-step explanation:

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3 years ago

The ratio of elena's height to pavai's height is 10:13. The ratio of elena's height to kamir's height is 2:3. Their total height

tensa zangetsu [6.8K]

Answer:

a) 10:13:3

b) 258 cm

Step-by-step explanation:

The ratio of elena's height to pavai's height is 10:13. The ratio of elena's height to kamir's height is 2:3. Their total height is 456 cm.

a) Find the ratio of elena's height to pavani's height to kamir's height in its simplest form.

10:13:3

b) What is pavani's height?

The ratio of elena's height to pavai's height is 10:13.

Their total height is 456 cm

Sum of proportions = 10 + 13 = 23

Hence:

13/23 × 456 cm

= 257.73913043 cm

Approximately = 258 cm

3 0

3 years ago

√3xy^3 • √8xy^4 =<br> i need steps too.

liubo4ka [24]

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

2x²y exponit 7√6

3 0

3 years ago

Read 2 more answers

5x + 1 = 56<br><br> Solving 2 step equations?

frutty [35]

Answer:

the x would equal to 11 ,so x=11

4 0

3 years ago

Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in

tatuchka [14]

Answer:

The equation representing how old Monique son is $\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

$q(t) = \hat q \times t + q_o$

where;

$q_o$ = initial height of Monique's son

$\hat q$ = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

$\hat q = 2 \dfrac{5}{8} \ in/yr$

$\hat q = \dfrac{21}{8} \ in/yr$

Then; from the equation $q(t) = \hat q \times t + q_o$

$34 = \dfrac{21}{8} \times 0 + q_o$

$q_o = 34\ inches$

The height of the son as a function of the age can now be expressed as:

$q(t) = \dfrac{21}{8} \times t + 34$

Then:

Making t the subject;

$q - 34 = \dfrac{21}{8} \times t$

$t = \dfrac{8}{21}(q-34)$

and the age of the son i.e. ( a (in years)) is:

a = 2 + t

So;

$\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

SO;

if q (growth rate) = 50 inches tall

Then;

$\mathbf{a = 2 + \dfrac{8}{21}(50-34)}$

$\mathbf{a = 2 + \dfrac{8}{21}(16)}$

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0

2 years ago