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insens350 [35]
3 years ago
5

What is the value of the expresion?

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer: D

Step-by-step explanation:

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Could someone please help me?
SpyIntel [72]

Answer:

ab=9 and ac=12

Step-by-step explanation:

3 0
3 years ago
What is the value of x?
QveST [7]

Answer:

72°

Explanation:

Given that line J and line K are parallel, we can safely assume that line m is the transversal for the following question. We can also remove line l so that we can focus on line m instead.

Using the rule of <u>Alternate Exterior Angle</u> theorem, x would equal to 72°.

7 0
3 years ago
Read 2 more answers
3<br> (<br> x<br> +<br> 7<br> )<br> &lt;<br> 7<br> (<br> x<br> +<br> 2<br> )
Gre4nikov [31]
3(x+7)<7(x+2)

Inequality Form: x>7/4
Interval Notation: (7/4, infinity)
5 0
3 years ago
KHAN ACADEMY! PLEASE HELP!
Brilliant_brown [7]

Answer:

60 degrees

Step-by-step explanation:

First find angle I by using the sum of the angles in a triangle is 180 degrees

59+61+I = 180

120 + I = 180

I = 180-120

I =60

<I = <x since they are corresponding angles

<x = 60 degrees

3 0
3 years ago
Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.
Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = n^{3}+2n+3n^{2}

for n=1

P(n)  = 1^{3}+2(1)+3(1)^{2} = 6

It is divisible by 2 and 3

Now, for n=k, n > 0

P(k) = k^{3}+2k+3k^{2}

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = (k+1)^{3}+2(k+1)+3(k+1)^{2}

P(k+1) = k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3

P(k+1) = P(k)+3(k^{2}+3k+2)

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = n^{3}+2n+3n^{2} is divisible by 2 and 3 for all positive integer n.

3 0
3 years ago
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