Answer:
7 or 8
Step-by-step explanation:
Robbie was given $80.
His admission costs $15.50
80 - 15.50 = $64.50
He anticipates the cost of food at the fair will be $25.
64.50 - 25 = $39.50
What is the maximum number of rides he can take at the Fair?
(Total $ after admission and cost of food/ ride cost)
$39.50 / $5 = 7.9
W0W alot........
2. 16/5c
3. 3q/2r^2
4. 1
5. yw^2/z^3x^3
6. 20j
7. 0 + m^2-m+m+1/m^2-m
8. 1- 1/b+2
H0P3 It H3LPS :)
#Itwashardwork
Go to 32 questions at random, buy some gas there, take the data and boom, you got an answer.