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Anit [1.1K]
4 years ago
7

(-2-4i) + (1+6i) how do you do this question

Mathematics
1 answer:
lesantik [10]4 years ago
6 0
For this equation you would need to combine like terms
Step 1: -2+1= -1
Step 2: -4i+6i= 2i
so your answer to this question would be -1+2i
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The coordinates of point T are (0,4). The midpoint of ST is (6,-7). Find the coordinate of point S
Ne4ueva [31]

Answer:

Step-by-step explanation:

(x + 0)/2 = 6

x + 0 = 12

x = 12

(y + 4)/2 = -7

y + 4 = -14

y = -18

(12, -18)

5 0
3 years ago
QUESTION 5 of 10: You are considering selling your home. You consult with an agent who gives you the asking prices of five homes
Diano4ka-milaya [45]

Answer: $169,500

Step-by-step explanation:

The mean simply means the average price of a set of a numbers that are given. For one t calculate the mean, one has to add the numbers that are given and then divide them by the amount of numbers.

I'm the case above, the numbers given are $165,000, $188,000, $175,000, and $150,000.

Mean = ($165,000 ,+ $188,000 +$175,000 + $150,000) ÷ 4

= $678,000/4

= $169,500

5 0
3 years ago
Which of the following statements is true
il63 [147K]

Answer:

I'm not sure cause their are no statements!

Step-by-step explanation:

None!

7 0
4 years ago
Can someone please help? if can include working out​
artcher [175]

Answer:

8

Step-by-step explanation:

you add all of it up together

6 0
3 years ago
The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions o
Step2247 [10]

Given:

Perimeter of a football field = 920 feet.

The width is 60 feet more than one-third of the length.

To find:

The dimensions of a football field.

Solution:

Let the length of the field be x.

Then, width = \dfrac{1}{3}x+60

We know that,

Perimeter = 2( length + width)

920 = 2(x+\dfrac{1}{3}x+60)

920 = 2(\dfrac{4}{3}x+60)

920 =\dfrac{8}{3}x+120

Subtract both sides by 120.

920-120 =\dfrac{8}{3}x+120-120

800 =\dfrac{8}{3}x

Multiply both sides by 3.

2400 =8x

Divide both sides by 8.

300 =x

Now,

Length = 300\text{ feet}

Width=\dfrac{1}{3}(300)+60

Width=100+60

Width=160\text{ feet}

Therefore, the length and width of the football field are 300 feet and 160 feet respectively.

7 0
3 years ago
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