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ohaa [14]
3 years ago
12

PLEASE WILL SOMEONE HELP ME? i WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
Fed [463]3 years ago
4 0

B ∪ (C' ∩ A)

Starting from the inside, C' ∩ A is the intersection of not C, which is everything except the circle C, and A.  That's the part I shaded in bright blue.

That's unioned with B, which is just all of the circle B.  I shaded the parts of B that I didn't already shade with a grey-blue.

These should all be the same shade; I just made them slightly different for explanation.

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4|n|-5=7 please help me solve
DedPeter [7]
I think you meant to type

4(n)-5=7.

4n = 7 + 5

4n = 12

n = 12/4

n = 3
3 0
3 years ago
Read 2 more answers
What is 6/13 rounded to the nearest half?
prohojiy [21]
6/13, when turned into a decimal, is equal to 0.4615384615... And so on. That decimal can be rounded to the nearest hundredth to become 0.46.

Is 0.46 closer to 0.5, or 0? When put on a number line, we can see how close it is to 0.5, which is the same as 1/2.

6/13, rounded to the nearest half, is 1/2.
Hope this helped =)
6 0
3 years ago
Read 2 more answers
What are the characteristics of the graph of the inequality x ≥ -2? The ray will move to the left. The ray will move to the righ
Alenkasestr [34]

Answer:

Step-by-step explanation:

The inequality x ≥ -2 is graphed on a number line.  -2 is the smallest possible value.  All subsequent values are larger and therefore lie to the right of -2.

Thus, the following are true:

1.  The ray will move to the right (because x begins at -2 and increases, which means moving to the right on the number line).

2.  It will use a closed circle (because x = -2 is part of the solution set).

6 0
3 years ago
Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25​
Oxana [17]

Answer:

1

Step-by-step explanation:

\huge {625}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div 25 \\  \\ =  \huge {( {5}^{4})}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\  =   \huge{5}^{ \cancel4 \times  \frac{3}{ \cancel8 \:  \:  \red{ \bold 2}} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ \frac{3}{2} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\ \huge=  {5}^{ \frac{3}{2}  + \frac{1}{2}}  \div  {5}^{2}  \\ \\ \huge=  {5}^{ \frac{4}{2}  }  \div  {5}^{2}  \\ \\ \huge=  {5}^{ 2  }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ 2  - 2 }  \\  \\   \huge=  {5}^{ 0 }  \\  \\   \huge=  1

5 0
3 years ago
Find the volume of a pyramid with a square base, where the perimeter of the base is 13.4 in and the height of the pyramid is 7.6
VashaNatasha [74]

Answer:

28.4in³

Step-by-step explanation:

Volume of the square based pyramid = L²H/3 where;

L is the length of a side of the square base

H is the height of the prism

Given

Perimeter of the base = 13.4 in

Height of the pyramid = 7.6in

First we need to get the length of the square base

Perimeter of a square = 4L

13.4 = 4L

L = 13.4/4

L = 3.35 in

Next is to find the required volume of the pyramid

V = L²H/3

V =  3.35²(7.6)/3

V = 85.291/3

V =  28.4 in³

Hence the volume of the pyramid to nearest tenth is 28.4in³

7 0
3 years ago
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