Ask question

Ask question

All categories

3 years ago

10

At the beginning of a month your account balance was $53. During the month you deposited $562 and wrote a check for $486. What w

as your balance at the end of the month

1 answer:

alexdok [17]3 years ago

5 0

53+562-486= 129

Add then subtract

You might be interested in

Simplify by dividing negative three over eight divided by five over nine..

IRISSAK [1]

Answer:

-15/24 or -0.625

Step-by-step explanation:

-3/8 ÷ 5/9

First, we can use the multiplication fraction conversion trick to switch the last fraction's numerator and denominator

It would look like this: -3/8 x 9/5

Use the cross out method to simplify the fractions as lowest as possible

-1/8 x 3/5 = -15/24

6 0

4 years ago

Aflati al 2013 lea termen al unei progresii aritmetice cu termenul al treilea egal cu 12 si diferenta a doi termeni consecutivi,

KATRIN_1 [288]

Răspuns:

8052

Explicație pas cu pas:

Al treilea termen al unei progresii aritmetice:

T (n) = a + (n - 1) d

Unde ;

a = primul termen; d = diferență comună = 4; n = al treilea termen (numărul termenului)

Al treilea (3) termen:

T (3) = a + (3-1) 4

T (3) = 12

12 = a + 2 (4)

12 = a + 8

12 - 8 = a

4 = a

Prin urmare, primul termen = a

Al 2013-lea mandat;

T (2013) = a + (2013-1) d

T (2013) = 4 + (2012) 4

T (2013) = 4 + 8048

= 8052

4 0

3 years ago

Six times the product of eleven and two

Pie

11x2=22

22x6=132

I believe the answer is 132

8 0

3 years ago

1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$

2. $x=\pm7i[tex]3.[tex]\pm 12x =a$

4. 22

Step-by-step explanation:

1. $n^2 - 49 = 0$

$n^2 =49$

$n= \sqrt{49}$

$n=\pm7$

2. $x^2+64 = 0$

$x^2 =-64$

$x= \sqrt{49}$

$x=\pm7i[tex]3. Area of square = [tex]a^{2}$

Where a is the side

We are given an area o square = $144x^{2}$

So, $144x^{2}=a^{2}$

$\sqrt{144x^{2}}=a$

$\pm 12x =a$

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

$(x+9)(x-9)=0$

$x^2- 81=0$

So, in the given equation $x^2 + z = 103$

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

$x^2 + 22 = 103$

$x^2 + 22 -103=0$

$x^2 -81=0$

Thus the value of z is 22

8 0

3 years ago

Read 2 more answers

Is x-1 a factor of x^5+2x^2-1

vazorg [7]

Answer: i think no cuz f(1)=2 but i am not sure

Step-by-step explanation:

5 0

3 years ago