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postnew [5]
3 years ago
5

Suppose the sample space for a continuous random variable is 0 to 400. If

Mathematics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

P(72 ≤ x ≤ 400) = 0.82. Correct: C.

Explanation:

<u>Probability Distribution</u>

In any probability distribution, the total probability of the sample space must be 1.

Since the sample space is given as a random variable x that takes values from 0 to 400, then:

P(0 ≤ x ≤ 400) = 1

For any value of x:

If the sample space is divided into two parts like:

P(0 ≤ x ≤ 72) and P(72 ≤ x ≤ 400), then the combined probability must be 1:

P(0 ≤ x ≤ 72) + P(72 ≤ x ≤ 400) = 1

Or, equivalently:

P(72 ≤ x ≤ 400) = 1 - P(0 ≤ x ≤ 72)

P(72 ≤ x ≤ 400) = 1 - 0.18

P(72 ≤ x ≤ 400) = 0.82

A. The value 0.92 is not correct since does not match with the value 0.82.

B. The value 0.18 is not correct since does not match with the value 0.82.

C. This is the correct value. Correct Choice

D. The value 0.982 is not correct since does not match with the value 0.82.

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2 years ago
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Answer:

a. P(male) = 0.4

b. P(no sport and male) = 0.1

c. Unclear question (isn't it the same as b.?)

Step-by-step explanation:

The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;

\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]

a.

P(male) = \frac{7 + 21}{70} \\\\ = \frac{28}{70} \\\\ = \frac{2}{5}

b.

Using the tree diagram in the picture;

P(no \ sport \ and \ male) = \frac{2}{5} * \frac{1}{4} \\\\ = \frac{1}{10}

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2 years ago
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Answer:

3/9

Step-by-step explanation:

15/45

divide both sides by a factor of each number; I'll be using 5.

3/9

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The answer is A. Adjacent
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Step-by-step explanation:

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