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yKpoI14uk [10]
3 years ago
5

Anyone know how to do this?

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0
This is the worst I hate these. I will try to help though give me one minute.
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Solve the equation for a.
Pavel [41]

Answer:

\large\boxed{a=\dfrac{K}{4+9b}}

Step-by-step explanation:

K=4a+9ab\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\K=a(4+9b)\qquad\text{divide both sides by}\ (4+9b)\neq0\\\\\dfrac{K}{(4+9b)}=\dfrac{a(4+9b)}{(4+9b)}\\\\\dfrac{K}{4+9b}=a

6 0
3 years ago
Read 2 more answers
Mr. Gardner is making 6 treat bags. He has 185 chocolate-covered raisins to share evenly among the treat bags.
Degger [83]
To find out the answer, we need to divide 185 by 6.

185÷6=30 with a remainder of 5.

There are going to be 30 <span>chocolate-covered raisins in each bag, with 5 of them left over.

I hope this helps.</span>
7 0
3 years ago
Read 2 more answers
Which equation can be used to find B in the triangle below?
WINSTONCH [101]

9514 1404 393

Answer:

  (b)  tan B = 8/6

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relevant relationships:

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

Then angle B is involved in tangent and cosine relationships this way:

  tan B = 8/6 . . . . . . matches 2nd choice

  cos B = 6/10 . . . . . matches no choices

_____

<em>Additional comment</em>

Both of the offered cosine choices give a cosine value that is greater than 1. The cosine of a real angle is never greater than 1, so those can be rejected immediately.

8 0
3 years ago
A town has a population of 8000 and grows at 3% every year. To the nearest tenth of a year, how long will it be until the popula
Alexxx [7]

Answer:

It will take approximately 34 years

Step-by-step explanation:

If a town population is 8000 and grows 3% annually.

How long will it take to reach 16300

growth is 16300 - 8000 = 8300

using simple interest formula

SI = (P × r × t)/100

8300 = (8000 × 3 × t)100

8300= (80 × 3)t

8300 = 240t

t = 8300/240

t ≈ 34 years to the nearest tenth

8 0
3 years ago
How many positive integers less than 1000 a) are divisible by 7? b) are divisible by 7 but not by 11?
sashaice [31]

Answer:

  130

Step-by-step explanation:

The number of integers meeting the criteria can be found by counting them using a counting formula.

<h3>Divisible by 7</h3>

Integers divisible by 7 will have the form (7n), where n is some positive integer. The number of them less than 1000 can be found from ...

  7n ≤ 1000

  n ≤ 142.857

There are 142 integers less than 1000 that are divisible by 7.

<h3>Divisible by 7 and 11</h3>

Similarly, integers divisible by 7 and 11 will be of the form (77n), for some positive integer n.

  77n ≤ 1000

  n ≤ 12.987

There are 12 integers less than 1000 that are divisible by both 11 and 7.

<h3>Divisible by 7, not 11</h3>

The number of integers less than 1000 that are divisible by 7, but not 11, will be the difference of these numbers.

  142 -12 = 130 integers divisible by 7, but not 11.

3 0
2 years ago
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