For every c substitute 4 and for every d substitute -2
c=4
d=-2
6c + 5d - 4c - 3d + 3c - 6d
= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)
=24+(-10)-16-(-6)+12-(-12)
=24-10-16+6+12+12
=28
The formula for the midpoint is:
(x1 + x2)/2, (y1 + y2)/2
Midpoint = (5+3)/2 , (7+1)/2
Midpoint = 8/2 , 8/2
Midpoint =(4,4)
2 13/25 is equivalent to 63/25.
Answer:
The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.
Step-by-step explanation:
We have given,
The sample size n=42
The sample mean ![\bar{x}=30](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D30)
The population standard deviation ![\sigma=7.4](https://tex.z-dn.net/?f=%5Csigma%3D7.4)
Let
be the level of significance = 0.05
Using the z-distribution table,
The critical value at 5% level of significance and two tailed z-distribution is
![\pm z_{\frac{0.05}{2}}=\pm 1.96](https://tex.z-dn.net/?f=%5Cpm%20z_%7B%5Cfrac%7B0.05%7D%7B2%7D%7D%3D%5Cpm%201.96)
The value of margin of error is
![ME=z_{\alpha/2}(\frac{\sigma}{\sqrt{n}})](https://tex.z-dn.net/?f=ME%3Dz_%7B%5Calpha%2F2%7D%28%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%29)
![ME=1.96(\frac{7.4}{\sqrt{42}})](https://tex.z-dn.net/?f=ME%3D1.96%28%5Cfrac%7B7.4%7D%7B%5Csqrt%7B42%7D%7D%29)
![ME=1.96(1.1418)](https://tex.z-dn.net/?f=ME%3D1.96%281.1418%29)
![ME=2.238](https://tex.z-dn.net/?f=ME%3D2.238)
The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.