HELP ME ILl MARK BRAINLIEST
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To find the vertex of the parabola, we need to write it in a vertex form.
y=x² - 8x +12
1) complete the square
y=x² - 8x +12
y = x² -2*4x + 4² - 4² +12
y=(x-4)² -16 +12
2) calculate and write a vertex
y=(x-4)² -16 +12
y=(x-4)² - 4
(x-4) ----- x- coordinate of the vertex x=4
y=(x-4)² - 4 -------y- coordinate of the vertex y = - 4
Vertex is (4, -4).
Answer is (4, -4). No correct answer is given in choices.
y=x² - 8x +12
1) complete the square
y=x² - 8x +12
y = x² -2*4x + 4² - 4² +12
y=(x-4)² -16 +12
2) calculate and write a vertex
y=(x-4)² -16 +12
y=(x-4)² - 4
(x-4) ----- x- coordinate of the vertex x=4
y=(x-4)² - 4 -------y- coordinate of the vertex y = - 4
Vertex is (4, -4).
Answer is (4, -4). No correct answer is given in choices.
Since the lines are parallel and you know the slope of 
is -2, you know the slope of line 
will also be -2. You can see on the coordinate grid that line crosses the y-axis at -1. When you piece all of these facts together into slope-intercept form you get = -2x - 1.
Answer:
.
Step-by-step explanation:
On a cartesian plane, the -intercept of a function is the point where the graph of that function intersects with the
-axis.
The -axis of a cartesian plane is the same as the equation
(that is, the collection of all points with an
-coordinate of
.)
Construct a system of two equations, with one equation representing -axis and
to represent the graph of this function:
.
Solve this system for and for
. If a solution exists, then the
-axis and the graph of
would indeed intersect. The point
would be the intersection of the
-axis and the graph of
.
Substitute the second equation of the system into the first.
.
Hence, the intersection of the -axis and the graph of
would be
. By definition, this point would be the
-intercept of
.