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fiasKO [112]
3 years ago
14

There are 16 games played in a regular season of football. The Dallas Cowboys win the first game of the season. They then lose t

he next two games, followed by a six win streak. What is the probability that the Dallas Cowboys will win game 11 of the football season?
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
4 0

Since there are 16 games, I will make 16 slots

| ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? |

I will use W for a win and L for a Loss.

| W | L | L | W | W | W | W | W | W | ? | ? | ? | ? | ? | ? | ? |

However, this is a trick question!

The information given is irrelevant.

There is a 50 50 chance of any team winning any game

So there is a 50% probability that they will win game 11.

Hope that helps!



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First use the property of logarithms

\log _ab-\log_ac=\log_a\dfrac{b}{c}.

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\log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2+8} }=\log_w(x^2-6)^4-\log_w\sqrt[3]{x^2+8}=\log_w(x^2-6)^4-\log_w(x^2+8)^{\frac{1}{3}}

Now use property of logarithms

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\log_w(x^2-6)^4-\log_w(x^2+8)^{\frac{1}{3}}=4\log_w(x^2-6)-\dfrac{1}{3}\log_w(x^2+8).

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