The vertex of a parabola is its highest or lowest point. Here, it is the lowest point, which happens right at the bottom of the U-shape—at (1, –4). Therefore, the answer is C.
Answer:
x = 5 or x = 1
Step-by-step explanation:
Absolute Value Equation entered :
3|3x-9|=18
Step by step solution :
Step 1: Rearrange this Absolute Value Equation
Absolute value equalitiy entered
3|3x-9| = 18
Step 2: Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is 3|3x-9|
For the Negative case we'll use -3(3x-9)
For the Positive case we'll use 3(3x-9)
Step 3: Solve the Negative Case
-3(3x-9) = 18
Multiply
-9x+27 = 18
Rearrange and Add up
-9x = -9
Divide both sides by 9
-x = -1
Multiply both sides by (-1)
x = 1
Which is the solution for the Negative Case
Step 4: Solve the Positive Case
(3x-9) = 18
Multiply
9x-27 = 18
Rearrange and Add up
9x = 45
Divide both sides by 9
x = 5
Which is the solution for the Positive Case
Step 5: Wrap up the solution
x=1
x=5
Solutions on the Number Line
Two solutions were found :
x=5
x=1
Answer:
x is 67
Step-by-step explanation:
angles on a straight line.
<u>Answer:</u>
- The cost of 1 dozen doughnut is $6 and the cost of a dozen croissant is $10.
<u>Step-by-step explanation:</u>
<u>We know that:</u>
- D = Cost of a dozen doughnut
- C = Cost of a dozen croissant
- 10D + 7C = 130
- 6D + 4C = 76
<u>Work:</u>
6D + 4C = 76
7(6D + 4C = 76)
42D + 28C = 532
- 40D - 42D = 520 - 532
- => -2D = -12
- => 2D = 12
- => D = 6
<u>Now, let's substitute the value of D into the first equation.</u>
- 10D + 7C = 130
- => 10(6) + 7C = 130
- => 60 + 7C = 130
- => 7C = 70
- => C = 10
Hence,<u> the cost of 1 dozen doughnut is $6 and the cost of a dozen croissant is $10.</u>
Hoped this helped.
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Answer:
Step-by-step explanation:
Given the order of operations A set of three scores to consists of the values 6, 3, and 2, we are to evaluate the following
1) Σ2X – 2
= 2(6)+2(3)+2(2) – 2
= 12+6+4–2
= 22–2
= 20
2) Σ(2X)² = (2×6)²+(2×3)²+(2×2)²
Σ(2X)² = 12²+6²+4²
Σ(2X)² = 144+36+16
Σ(2X)² = 144+52
Σ(2X)² = 196