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Crank
3 years ago
13

Plz help so i can talk to friends

Mathematics
2 answers:
dimulka [17.4K]3 years ago
5 0

I THINK IF I READ THAT RIGHT XD

9..IS A

10...IS D

viktelen [127]3 years ago
4 0
9.
A quadrilateral has 4 vertices. If you add two bases, its like adding two vertices. 4+2=6. A figure that has 6 vertices is a hexagon, so the answer is hexagon.

10.
Rhombus


Good luck!
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2.64-2.14\frac{1.32}{\sqrt{15}}=1.911    

2.64+2.14\frac{1.32}{\sqrt{15}}=3.369    

So on this case the 95% confidence interval would be given by (1.911;3.37)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=2.64 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=1.32 represent the sample standard deviation

n=15 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,14)".And we see that t_{\alpha/2}=2.14

Now we have everything in order to replace into formula (1):

2.64-2.14\frac{1.32}{\sqrt{15}}=1.911    

2.64+2.14\frac{1.32}{\sqrt{15}}=3.369    

So on this case the 95% confidence interval would be given by (1.911;3.37)    

6 0
3 years ago
How do I complete the table
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3 years ago
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