A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb
</span>B) First, find the z-score:
z = (value - mean) / stdev
= (150 - 199) / 41
= -1.20
We need to find P(z > -1.20) = 1 - P(z < -1.20)
Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849
Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>
C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb
Let's repeat the steps of point B)
z = (187.5 - 199) / 41
= -0.29
P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141
</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%
D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
= 3750 </span></span><span>÷ 199
= 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
Standard form is ax+by=c
normally a is positive and a and b are integres
y=mx+b
m=slope
b=yint
y=1/2x+3
minus 1/2 x both sides
-1/2x+y=3
times -2
x-2y=-6
Answer:
She needs to number each plant 1–60 and randomly select 10 plants
Step-by-step explanation:
Answer:
Graph B
This is because of the vertical line test. Say you were to draw a vertical line that stretches through the whole graph. If this line you draw passes through more than two points of the same line/function/whatever b is, it is not a function.
Answer:
200,000 m
Step-by-step explanation:
We will multiply the length of the ant by the number of ants to find out how long the line is.
10 million is 10 with 6 zeros
20 * 10 ^-3 move the decimal 3 places to the left
20. * 10 ^-3 = .02
.02 * 10000000
200000
