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3 years ago

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The students in the cooking club brought sugar to class they each brought 3,4,5and 6cups of sugar respectively they divided the

sugar email so that each student receive the same number of cups of sugar how many cups of sugar did each student get

1 answer:

geniusboy [140]3 years ago

3 0

Answer:

if there is 4 students then each student gets about 4 1/2 cups of sugar.

Step-by-step explanation:

3+4+5+6=18

18/4=4.5

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7x² + 6x - 1<br> Algebra 3|factoring

GaryK [48]

Answer:

(7 x - 1) (x + 1)

Step-by-step explanation:

Factor the following:

7 x^2 + 6 x - 1

Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):

(7 x - 1) + x (7 x - 1)

Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):

Answer: (7 x - 1) (x + 1)

5 0

3 years ago

Find the equation of the line specified.

OLga [1]

The point slope form of a straight line is y-y1 = m(x-x1)

y -(-3) = -7(x-5)

y + 3 = -7(x-5)

y = -7x + 35 - 3

y = -7x + 32

7 0

3 years ago

Find the area of each figure

Anon25 [30]

Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2

Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2

7 0

2 years ago

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 5x - 7x + 11?

Maksim231197 [3]

Answer:

±1, ±11, ±1/5, ±11/5

Step-by-step explanation:

f(x) = 5x³ - 7x + 11

constant term: 11

leading coefficient: 5

factors of the constant term: ±1, ±11

factors of the leading coefficient: ±1, ±5

possible rational roots = factors of the constant term/factors of the leading coefficient = ±1, ±11, ±1/5, ±11/5

6 0

2 years ago

1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

Part 2

The original margin of error is given by:

$ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

3 0

2 years ago