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Butoxors [25]
4 years ago
15

There are 10 students in a classroom, including the triplets Hugh,Stu, ans Lou. if 3 of 10 are randomly selected to give speeche

s, what is the probability that Hughs will be first ,Stu will be second, and Lou will be third?
Mathematics
1 answer:
Brrunno [24]4 years ago
7 0
P(Hugh) = 1/10
P(Stu) = 1/9
P(Lou) = 1/8

Required probability = 1/10 * 1/9 * 1/8  = 1/720
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Step-by-step explanation:

a equals c over x minus b over x

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3 years ago
Consider the temperature versus time graph below.
Viktor [21]

Answer:

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Step-by-step explanation:

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3 years ago
Calen is comparing the prices per child for hosting a birthday at Mr. Bob’s Buffet and Sally’s Pizza Safari.
madreJ [45]

The cost per child per child is $10 more at Mr Bob's buffet than it is at Sally's pizza safari.

Answer: Option 3.

<u>Explanation:</u>

According to the data and the information that has been given in the question, the cost of four children for this birthday party at Mr Bob is $60. But the cost of hosting a birthday party at Mr Sally is $50 which is the cost of four children.

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3 years ago
Question: 3 of 20
zysi [14]

Answer:

Sean earns $7.5 in each hour.

Step-by-step explanation:

Given:

Money earned by Sean = $300

Number of hours worked in a day = 8 hrs

Number of days of work  in a week = 5

We need to find Money earned in each hour.

First we will find Total hours work in a week.

Total hours work in a week is equal to Number of hours worked in a day multiplied by number of days work in a week.

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Total hours worked in a week = 8\times5 = 40\ hrs

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Money earned each hour will be calculated by Dividing Total Money earned in a week by Total number of hours worked in a week.

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8 0
3 years ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
3 years ago
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