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Cloud [144]
3 years ago
5

What is area of a quadrilateral

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

So, area of quadrilateral ABCD = (½ × AC × BE) + (½ × AC × DF) We can calculate the area of different types of quadrilaterals by using the given formula. For the quadrilateral ABCD, if we use centimeter as the unit of measurement, the unit of measure for the area will be cm2 .

I hope it's helpful!

kifflom [539]3 years ago
5 0

Answer:

Step-by-step explanation:

R u asking for formula ?

If so  then,

1/2 x (h1+h1 )d

which is half the sum of height 1 and 2 multipied by daigonal

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PLEASE HELP PLEASE THANKS
ddd [48]

Answer:

P=23.9\ inches

Step-by-step explanation:

<u>Formula Evaluation</u>

Formulas are expressions where a sequence of letters, numbers or symbols have a determined meaning in given system.

Formulas are usually expressed as mathematical operations that connect one or more variables.

The perimeter of a triangle is the sum of the lengths of its sides. Being a,b, and c their sides, then the perimeter has the formula

P=a+b+c

We are given the values of

a=13\ inches

b=7.2\ inches

c=3.7\ inches

Thus the perimeter is

P=13\ inches+7.2\ inches+3.7\ inches

\boxed{P=23.9\ inches}

5 0
4 years ago
Construction crew is using heavy equipment to dig a hole in which the foundation of a house will be built. The whole will be in
frosja888 [35]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Please answer asap. pretty sure I know the answer just need to be certain.
astra-53 [7]
  • Answer:

<em>p = 4$</em>

  • Step-by-step explanation:

<em>p + 25%p = $5</em>

<em>p + 25p/100 = 5</em>

<em>⁴⁾p + p/4 = ⁴⁾5</em>

<em>4p + p = 20</em>

<em>5p = 20</em>

<em>p = 20 : 5</em>

<em>p = 4$</em>

4 0
3 years ago
Find the solution of y = 6x + 1 for x = 5.
Arte-miy333 [17]

Answer:

D.) (5,31)

Step-by-step explanation:

Since they already gave you the value of x

plug that into the equation for y

y=6(x)+1

y=6(5)+1

y=30+1

y=31

Therefore, you have

x=5 and y=31

(5,31)

HOPE THIS HELPS!

7 0
3 years ago
Read 2 more answers
Find the equation of the median from b in ABC whose vertices are (1,5), B(5,3) and C(-3, -2)
Soloha48 [4]

Answer:

y = x + 6

x = 1

y = ¼(x - 5) + 3

Step-by-step explanation:

Vetices are;

A(1,5), B(5,3) and C(-3, -2)

Thus;

Median of AB is; D = (1 + 5)/2, (5 + 3)/2

D = (3, 4)

Median of BC is; E = (5 + (-3))/2, (3 + (-2))/2

E = (1, 0.5)

Median of AC is; F ; (-3 + 1)/2, (-2 + 5)/2

F = (-1, 1.5)

Thus, the median lines will be;

CD, AE & BF.

Thus;

Equation of CD is;

(y - (-3))/(x - (-2)) = (-2 - 4))/(-3 - 3)

(y + 4)/(x + 2) = -6/-6

y - 4 = 1(x + 2)

y = 4 + x + 2

y = x + 6

Equation of AE;

(y - 5)/(x - 1) = (0.5 - 5)/(1 - 1)

(y - 5)/(x - 1) = -4.5/0

Cross multiply to get;

0(y - 5) = -4.5(x - 1)

-4.5x = -4.5

x = 1

Equation of BF;

(y - 3)/(x - 5) = (1.5 - 3)/(-1 - 5)

(y - 3)/(x - 5) = -1.5/-6

(y - 3)/(x - 5) = 1/4

y - 3 = ¼(x - 5)

y = ¼(x - 5) + 3

7 0
3 years ago
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