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3 years ago

The rational number halfway between 2/4 and 1/8

Mathematics

2 answers:

arsen [322]3 years ago

8 0

Answer: 5/16, or 0.3125

First, add the two fractions. Both fractions must have the same denominator.

2/4 → 4/8

1/8

4/8 + 1/8 = 5/8

Now, divide by 2:

5/8/2 = 5/16

I also found another way to solve this, if you're interested:

First, convert both fractions to their sixteenths form:

2/4: 8/16

1/8: 2/16

Then, identify the number midway between the numerators, being 5.

So, the answer is 5/16

galben [10]3 years ago

6 0

Answer:

one third or 0.333333...

Step-by-step explanation:

a rational number is a number that can be written as a ratio between two numbers. they an be repeating like 1/3 or terminating like 1.36.

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mestny [16]

Start by adding 2 to both sides to get 3r^2 = 48. then divide both sides by 3 to get r^2 = 16. square root both sides to get r = 4.

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3 years ago

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I need answers ASAP! Thanks!

Daniel [21]

Step-by-step explanation:

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3 0

2 years ago

3050÷ 75 with remainder

zlopas [31]

Answer:

122/3 or 40.666667

Step-by-step explanation:

7 0

3 years ago

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How do you solve 40.25 divided by 0.5

Aleksandr-060686 [28]

The answer correct answer is 80.5

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3 years ago

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Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

2 years ago