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Ksju [112]
3 years ago
12

27 outs in 9 innings Write the unit rate for the situation ;)

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0
I believe it’s 3!!!!
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(04.02 MC)
Scrat [10]

Answer:

y = 2x - 4

Step-by-step explanation:

Rearrange the given equation to slope-intercept form.

x + 2y = 2

2y = -x + 2

y = -1/2x + 1

The slope of the given line is -1/2.  The slope of a perpendicular line will be the negative inverse, meaning that the slope will be 2.

-1/2 = 2

Find the equation of the new line with the point-slope form using the new slope and given point.

y - y₁ = m(x - x₁)

y - 6 = 2(x - 5)

y - 6 = 2x - 10

y = 2x - 4

The equation will be y = 2x - 4.

7 0
4 years ago
Read 2 more answers
What is the product of 241.82x3.1
Dmitry_Shevchenko [17]

Answer:749.642

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which is the equation of a line that has a slope of 5 and passes through point (2, -3)?
saw5 [17]

Answer:

That's the answer I do it this way hope it helps

6 0
3 years ago
You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 201 km south and 194 km east. Mt. Rainier is locat
elixir [45]

Answer:

The answer is "0.0846276476".

Step-by-step explanation:

Let all the origin(0,0) of JBLM be  

Let the y-axis be north along with the vector j unit.  

But along the + ve x-axis is east, and all along with the vector unit i.  

And at (194,-201) that undisclosed position is  

Mt. Ris (56,-40) at  

Let the moment it gets close to the Mt. rainier bet.  

Oh, then,  

If we know, the parallel to the direction from the point was its nearest one to a path to a point,

Calculating slope:

\to m=\frac{y_2-y_1}{x_2-x_1}\\

points:  (0,0) and (194,-201)

\to m=\frac{-201 -0 }{194-0}\\\\\to m=\frac{-201}{194}\\\\\to m=-1.03

equation of the line:

\to y= mx+c\\\\\to y= -1.03\ x+c

when the slope is perpendicular= -\frac{1}{m}

                                                     = - \frac{1}{ -1.03}\\\\= \frac{1}{ 1.03}\\\\= 0.97

perpendicular equation:

\to y-(-40)=0.97  \times (x-56) \\\\\to y+40=0.97  \times (x-56) \\\\

Going to solve both of the equations to have the intersection point,  

We get to the intersect level in order to be at

(47.16,-48.5748)

so the distance from origin:

= \sqrt{(47.16^2+48.5748^2)}\\\\= \sqrt{2224.0656 + 2359.5112}\\\\=\sqrt{4583.5768}\\\\=67.7021181

\to time =\frac{distance }{speed}

= \frac{67.7021181}{800}\\\\= 0.0846276476

6 0
3 years ago
Write an equation for the line that passes through the points (0, -6) and (-3, 0).
mart [117]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-6)}{-3-0}\implies \cfrac{0+6}{-3}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=-2(x-0) \\\\\\ y+6=-2x\implies y=-2x-6

3 0
3 years ago
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