27 outs in 9 innings Write the unit rate for the situation ;)

Use the graph to write a linear function that relates y to x .

sergiy2304 [10]

Answer:

2y = x + 2

Step-by-step explanation:

Looking at the graph, we can see from one point to the next (from right to left), the x-value rises by 2 and the y-value by 1;

From this we can work out the gradient between two points using the formula, i.e. the change/difference in y divided by the change/difference in x:

$m = \frac{dy}{dx} = \frac{1}{2}$

Joining the points gives a straight line, which means a constant gradient of ¹/₂

Use the line equation formula to get the function:

y - y₁ = m(x - x₁)

m = ¹/₂

x₁ = 0

y₁ = 1

y - 1 = ¹/₂.(x - 0)

y - 1 = ¹/₂.x

2y - 2 = x

2y = x + 2

8 0

3 years ago

A sphere is inscribed in a cube with a volume of 64 cubic inches. What is the volume of the sphere? Round your answer to the nea

erma4kov [3.2K]

Answer:

the volume of the sphere is

$33.51 in^{3}$

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere and cube.

Given data

Volume of cube v = 64 cubic inches

since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,

we know that volume of cube is expressed as

$v= l*b*h$

$v=l^{3}$

$64= l^{3}$

$l= \sqrt[3]{64}$

$l= 4 in$

also diameter d=length l

Diameter d= $4in$

Radius r = $\frac{d}{2}$ = $\frac{4}{2}$ = ${2 in}$

Height h= $4in$

we know that the volume of a sphere is given by

$v= \frac{4}{3} \pi r^{3}$

substituting into the formula we have

$v= \frac{4}{3} \ *3.142*2^{3} \\v=\frac{4*3.142*8}3} \\v= \frac{100.54}{3} \\v= 33.52in^{3}$

8 0

3 years ago

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w

Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds. Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

$t = 5.0625$

Step-by-step explanation:

Given

$h(t)=-16t^2+80t+5$

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

$0=-16t^2+80t+5$

Reorder

$-16t^2+80t+5 = 0$

Using quadratic formula, we have:

$t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

Where

$a = -16$ $b =80$ $c = 5$

So, we have:

$t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}$

$t = \frac{-80\±\sqrt{6400 +320}}{-32}$

$t = \frac{-80\±\sqrt{6720}}{-32}$

$t = \frac{-80\±82.0}{-32}$

This gives:

$t = \frac{-80+82.0}{-32}$ or $t = \frac{-80-82.0}{-32}$

$t = \frac{2}{-32}$ or $t = \frac{-162}{-32}$

$t = -\frac{2}{32}$ or $t = \frac{162}{32}$

But time can not be negative.

So, we have:

$t = \frac{162}{32}$

$t = 5.0625$

Hence, time to hit the ground is 5.0625 seconds

3 0

3 years ago

If you want to go bed a 800 o'clock

Tpy6a [65]

Answer:

13 hours

Step-by-step explanation:

8:00 plus 4 is twelve ( 12 o'clock )

then you have 9hrs left.

( 4+9=13 )

4 0

3 years ago

A ladder 10 feet long rests against a vertical wall. Initially, the top of the ladder is 8 feet above the ground. If the top of

lora16 [44]

Step-by-step explanation:

Let vertical height of ladder from ground be y and

horizontal distance of the base of the ladder from the wall be x respectively.

Length of the ladder = l (constant) = 10 ft

Using Pythagoras theorem:

${l}^{2} = {y}^{2} + {x}^{2}$

Differentiate both sides w.r.t time

$0 = 2y \frac{dy}{dt} + 2x \frac{dx}{dt}$

$y \frac{dy}{dt} + x \frac{dx}{dt} = 0$

We know that (After 1 sec, y = 6 ft and x = 8 ft ; dy/dt = 2 ft/sec)

$6\times 2 + 8\frac{dx}{dt} = 0$

$\frac{dx}{dt} = - 1.5 ft \: per \: sec$

( Ignore - ive sign)

Therefore, bottom of the ladder is sliding away from the wall at a speed of 1.5 ft/sec one second after the ladder starts sliding.

8 0

3 years ago