I think it would be 2 soulutions
Answer:

Step-by-step explanation:
the general equation for a line is:

where
is the slope of the line, and
is the y-intercept.
Since we need a slope of -2/3:
,
So far we have that the line must have the equation:

the graph of a line with a negative slope is one that "falls" from left to right in the plane. And the number
means that it falls at a ratio of 2 units in the y-axis for every 3 in the x-axis.
we are told that the y-intercept is that of the line:
--> here the y-intercept is -2.
Thus the equation of the line we are looking for is:

which means that this line crosses the y-axis at -2, and the graph is the one in the attached image.
Answer:
A
Step-by-step explanation:
Note that
x² + 12x + 36 is a perfect square → (x + 6)², hence
=
= (x + 6)
Hence
f(x) × g(x)
= (x + 6)(x³ - 11)
=
- 11x + 6x³ - 66
=
+ 6x³ - 11x - 66 → A
Answer:
ye^(2x) - 3e^(2x) = C or (y - 3)e^(2x) = C
Step-by-step explanation:
dy/dx + 2y = 6
This is a first order linear ODE.
p(x) = 2
Integrating factor: I(x) = e^(∫ 2 dx) = e^(2x)
e^(2x)(dy/dx + 2y) = 6e^(2x)
e^(2x) dy + 2ye^(2x) dx = 6e^(2x) dx
Integrate both sides of the equation.
ye^(2x) = 3e^(2x) + C
Thus, the general solution is ye^(2x) - 3e^(2x) = C or (y - 3)e^(2x) = C.