Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
The distance between the hose and the point (P) is 0.9 miles
Step-by-step explanation:
Here we have
Speed of rowing the boat = 3 mph
Speed of waling = 4.5 mph
Since the speed of walking is more than that of to row the boat, the location of where he should dock his boat in order to minimize the total time he would need to reach the house is the shortest distance across the river to the house
Therefore the location of the point (P) should be directly opposite the house across the water and the distance id 0.9 miles.
Y = 5 x 3 + 8
y = 15 + 8
y = 23
True they could be congruent by ASA
Answer:
linear graph
Step-by-step explanation:
because the equation of the line is straight
