We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
Answer:
I would help you... But I think that you are supposed to have a picture and there is no picture.
Year Net Profit
1 <span>$14,250.00
2 $15,390.00
3 $16,621.20
4 $17,950.90</span>2
We need to get the increase of the net profit of the current year from the previous year.
Percentage increase = (Current year - Previous Year)/ Previous Year * 100%
Year 2: (15,390 - 14, 250) / 14,250 * 100% = 0.08 * 100% = 8%
Year 3: (16,621.20 - 15,390) / 15,390 * 100% = 0.08 * 100% = 8%
Year 4: (17,950.90 - 16,621.20) / 16,621.20 * 100% = 0.08 * 100% = 8%
Every year the net income increases by 8%. So, the net income in Year 5 will be:
17,950.90 x 1.08 = 19,386.97 Choice D.
ANSWER
The solution is
(x,y)=(1,-5)
EXPLANATION
The equations are:
1st equation: 6x +5y=-19
2nd equation: 12x-8y=52
Multiply the first equation by 2:
3rd equation: 12x +10y=-38
Subtracy the 2nd equation from the 3rd equations.
12x-12x+10y--8y=-38-52
18y=-90
Divide both sides by 18.
y=-5
Put y=-5 into any of the equations and solve for x.
Preferably, the first equation will do.
6x +5(-5)=-19
6x -25=-19
6x=25-19
6x=6
x=1
The solution is
(x,y)=(1,-5)
