Radius is half the circumference
c= 2(square root) pieA
This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.
Step-by-step explanation:
sorrry .......................
![\LARGE \int x^3 dx = \frac{x^4}{4}+C](https://tex.z-dn.net/?f=%5CLARGE%20%5Cint%20x%5E3%20dx%20%3D%20%5Cfrac%7Bx%5E4%7D%7B4%7D%2BC)
So the answer is choice D. You can check this by differentiating the right hand side and you'll get x^3 back again.
This answer can be found by using the power rule for integrals. That rule is