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deff fn [24]
3 years ago
5

Use the product, quotient, and power rules of logarithms to rewrite the expression as a single logarithm. Assume that all variab

les represent positive real numbers. (2 points)
2log x + 4log y
Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

log x²y^{4}

Step-by-step explanation:

Using the rules of logarithms

log x + log y ⇔ log xy

logx^{n} ⇔ n log x

Given

2logx + 4logy

= logx² + logy^{4}

= log x²y^{4}

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Jake can carry 6 1/4 pounds of wood in from the barn. His father can carry 1 5/7 times as much as jake. How many pounds can jake
Liono4ka [1.6K]
Jake Pauls Dad Can Carry 10.7 Pounds
8 0
4 years ago
g Given the following premises: (1) a∧(b∨a) (2) ~c→~a (3) ~g→~a (4) g→e (5)~(d∨h) Prove the Conclusion: c∧~h?
KIM [24]

Answer:

See the argument below

Step-by-step explanation:

I will give the argument in symbolic form, using rules of inference.

First, let's conclude c.

(1)⇒a  by simplification of conjunction

a⇒¬(¬a) by double negation

¬(¬a)∧(2)⇒¬(¬c) by Modus tollens

¬(¬c)⇒c by double negation

Now, the premise (5) is equivalent to ¬d∧¬h which is one of De Morgan's laws. From simplification, we conclude ¬h. We also concluded c before, then by adjunction, we conclude c∧¬h.

An alternative approach to De Morgan's law is the following:

By contradiction proof, assume h is true.

h⇒d∨h by addition

(5)∧(d∨h)⇒¬(d∨h)∧(d∨h), a contradiction. Hence we conclude ¬h.    

8 0
4 years ago
Determine whether the sequence converges or diverges. If it converges, give the limit. 48, 8, four divided by three, two divided
Inga [223]

Answer:

Converges, 57.6

Step-by-step explanation:

48, 8, 4/3, 2/9...

ratio = 8/48 = 1/6

A sequence converged if the ratio is between -1 and 1.

So, this sequence converges

Limit = a/(1-r)

Where a is the first term, and r is the common ratio

Limit = 48/[1 - (1/6)]

= 48/[5/6]

= 48 × 6/5

= 57.6

7 0
3 years ago
Read 2 more answers
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
Question is in the picture:
Sholpan [36]
Its 5 times larger.
3 0
4 years ago
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