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Rus_ich [418]
3 years ago
10

an item initially valued at 100$ goes down in value by 20% the first year then goes up in value 10% the second year and goes dow

n again by 20% in the third year. what is the value of the item at the end of the third year
Mathematics
1 answer:
Fed [463]3 years ago
8 0
$100 * 0.2 = $20.
$100 - $20 = $80.
$80 * 0.1 = $8.
$80 + $8 = $88.
$88 * 0.2 = $17.60
$88 - $17.60 = $70.40.
Answer: $70.40
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marissa [1.9K]
$12 5 times 3 is 15 -20% is $12
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3 years ago
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Solve the equation log^7b>2
ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is (\log b)^{7} > 2

⇒ \log b > 2^{\frac{1}{7} }

We are taking the base of the log here is 10.

So, 10^{(\log b)} > 10^{2^{\frac{1}{7} } } {Since 10^{\log x} =x and e^{\ln x} = x}

⇒ b > 12.71 (Approximate) (Answer)

3 0
3 years ago
An equilateral triangle has a side length of 6. What is the height of the triangle?
vlabodo [156]
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3. 

<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>

<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>

<span>Thus, the area of the upper triangle is: </span>

<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>

<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>

<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
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5 0
3 years ago
Read 2 more answers
Andre builds a form for a new cement step in the shape of a rectangular prism. The form he builds is 40 and 1/2 inches long, 10
posledela

Answer:

3240 in^3

Step-by-step explanation:

Step one:

given data

The dimension of the form

Length 40 and 1/2 inches long,

Depth 10 inches deep,

The width and 8 inches high

Step two:

The amount of cement is equivalent to the volume of the form

V=L*W*H\\\\V=40.5*10*8\\\\V=3240 in^3

Hence the volume of cement is 3240 in^3

8 0
3 years ago
Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope
Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

\pi = \frac{179}{523} = 0.3423

Then the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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