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tatyana61 [14]
3 years ago
10

Can someone pls help me on 4 and 5

Mathematics
1 answer:
never [62]3 years ago
5 0

Answer (4):

a=ub/k because

u=ak/b   (starting equation)

ub=ak    (multiply b to both sides)

a=ub/k   (divide both sides by k)

Answer (6)

x=g+c-y because

g=x-c+y  (starting equation)

x+y=g+c (add c to both sides)

x=g+c-y  (subtract y from both sides)

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Answer:

Step-by-step explanation:

Method 1: Taking the log of both sides...

So take the log of both sides...

5^(2x + 1) = 25

log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...

(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...

(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...

(2x)log 5 + log 5 - log 5 = log 25 - log 5

(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)

(2x)log 5 = log 5 <-- divide both sides by log 5

(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..

2x = 1

x=1/2

Method 2

5^(2x+1)=5^2

2x+1=2

2x=1

x=1/2

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