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tatyana61 [14]
4 years ago
10

Can someone pls help me on 4 and 5

Mathematics
1 answer:
never [62]4 years ago
5 0

Answer (4):

a=ub/k because

u=ak/b   (starting equation)

ub=ak    (multiply b to both sides)

a=ub/k   (divide both sides by k)

Answer (6)

x=g+c-y because

g=x-c+y  (starting equation)

x+y=g+c (add c to both sides)

x=g+c-y  (subtract y from both sides)

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How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c
VMariaS [17]
The answer is d. 5y − x = −10. 3y − x = 24

\frac{1}{5}x-2=  \frac{1}{3}x+8=y
⇒   y= \frac{1}{5}x-2
      y= \frac{1}{3}x+8
________________________
y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}
y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}
________________________
y= \frac{x-10}{5}            ⇒     5y=x-10
y= \frac{x+24}{3}           ⇒     3y=x+24
________________________
5y-x=-10
3y-x=24
5 0
3 years ago
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expeople1 [14]

Answer:

Center: (-3,-2)

Radius: √6

The graph is attached.

Step-by-step explanation:

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Where (h,k) is the  point of the center of the circle and r is the radius of the circle.

The equation given in the problem is

(x +3)^{2}+(y+2)^{2}=6

 Therefore:

h=-3

k=-2

The center is at (-3,-2)

And the radius is:

r^2=6\\r=\sqrt{6}

Then, you can graph it has you can see in the image attached.

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3 years ago
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Answer:

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