Answer:
y = 3/4 x - 5
Step-by-step explanation:
The slopes of perpendicular lines are negative reciprocals. We find the slope of the given line. Then we can find the slope of the reciprocal.
4x + 3y = -6
Solve for y.
3y = -4x - 6
y = -4/3 x - 2
The slope of the original line is -4/3.
The slope of the perpendicular is 3/4.
Now we need to find the equation of line with slope 3/4 that contains point (4, -2).
y = mx + b
-2 = (3/4)(4) + b
-2 = 3 + b
-5 = b
b = -5
The equation is
y = 3/4 x - 5
40 - x^2 = 0
x^2 = 40
x = + 40^0.5 or x = - 40^0.5
300-3x=33
Subtract 300 on both sides.
-3x=-273
Divide both sides by -3.
x=91
I hope this helps!
~kaikers
<span>
If BA is d units the CB must be 2d units. B is on the x-axis, 2d units
right of C so its coordinates are (2d, 0). A is d units above B at (2d,
d). </span>
