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lara31 [8.8K]
3 years ago
14

Hydroxylamine is a mutagen that acts only on cytosine and causes C-->T and G-->A base pair changes (i.e. it causes transit

ion mutations at GC sites). A normal sequence of a protein contains a PROLINE residue (pro) at a particular place. What new amino acid(s) would appear in place of the proline residue as a result of hydroxylamine mutagenesis?
Biology
1 answer:
natulia [17]3 years ago
7 0

Options for the question are not given. They are as follows:

a. arg or lys

b. ala

c. thr

d. leu or ser

e. Only termination codons

Answer:

d. leu or ser

Explanation:

Four codons code for proline amino acid. These are CCT, CCC, CCA, and CCG. Hydroxylamine causes C to change into T or G to change into A.

If first position is changed in each codon:

CCT = TCT (UCU)

CCC = TCC (UCC)

CCA = TCA (UCA)

CCG = TCG (UCG)

These codons produce Serine amino acid.

If second position is changed in each codon:

CCT = CTT (CUU)

CCC = CTC (CUC)

CCA = CTA (CUA)

CCG = CTG (CUG)

These codons produce Leucine amino acid.

Hence, out of the given options, option d. leu or ser is correct.

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An individual heterozygous for eye color, skin color, and number of eyes mates with an individual who is homozygous recessive fo
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Explanation:

Parentals:                     BbGgCc  x  bbggcc

The punette square diagram of the cross of these two parents is attached.

B = black eyes, b = orange eyes;

G = green skin, g = white skin;

C = two eyes, c = one eye

Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8

Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8

Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8

Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8

Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8

Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8

Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8

Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8

So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.

So, in view of above option B is most appropriate.

Note: In a trihybrid cross, a total of 64 progeny types may be produced.

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