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jek_recluse [69]
3 years ago
8

URGENT!!! PLEASE ANSWER!!!!!

Mathematics
2 answers:
tatiyna3 years ago
6 0

Answer: gabriel

Step-by-step explanation: when you have x and y,, they usually are equal to  1 and with gabriel's expression,, he made it simplier for us to solve but with his sister,, she just made it more different though both expressions are right,, but in the end gabriel is correct

meriva3 years ago
3 0
Gabriel is correct.
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During a four-week period, you worked the following hours: Week 1- 363 /8 hr; Week 2- 411 /4 hr; Week 3- 401 /2 hr; Week 4- 383
Dafna11 [192]
The average number of hours can be calculated using the following rule:
average number of hours = total number of hours / total number of weeks

total number of hours = 36 3/8 + 41 1/4 + 40 1/2 + 38 3/8 = 313/2 hours
total number of weeks = 4 weeks

Average number of hours per week = (313/2) / (4) = 39 1/8 hour

Based on the above calculations, the correct answer is:
C. 39 1/8 hour
4 0
3 years ago
A right rectangular prism has edges of 8 feet, 4 feet, and 1/2 foot. How many cubes with side lengths of 1/2 foot would be neede
Ksenya-84 [330]

Answer:

Step-by-step explanation:

From the question we are told that

Edges of 8 feet, 4 feet, and 1/2 foot

Generally the volume V_p of the right rectangular prism is mathematically represented as

V_p=8*4*0.5

V_p=16

Generally volume of the cube V_c is mathematically given as

V_c =(\frac{1}{2})^3

V_c =\frac{1}{6}

Therefore total number of cubes is given as

V=\frac{V_p}{V_c}

V=\frac{16}{\frac{1}{6}}

V=96

4 0
3 years ago
Evaluate tan45/sin30 . In your final answer, include all calculations.
Maslowich
From the identity \displaystyle{ \tan x= \frac{\sin x}{\cos x}, and from the values:

                 \sin45^{\circ}=\cos45^{\circ}= \frac{ \sqrt{2}}{2},

we have: \displaystyle{ \tan 45^{\circ}= \frac{\sin 45^{\circ}}{\cos 45^{\circ}}= \frac{ \frac{ \sqrt{2}}{2}}{\frac{ \sqrt{2}}{2}} =1.


We also know that \sin30^{\circ}= \frac{1}{2}.


Thus, \displaystyle{  \frac{\tan 45^{\circ}}{\sin30^{\circ}} = \frac{1}{\frac{1}{2}}=2.



Answer: 2
8 0
3 years ago
How many triangles can be constructed with side lengths of 9.6 cm, 11.6 cm, and 21.2 cm?
nignag [31]

Answer:  A) 0 triangles

============================================================

Explanation:

Adding up the two smaller sides gets us 9.6+11.6 = 21.2, but this result is not larger than the third side of 21.2

For a triangle to be possible, we need to be able to add any two sides and have the sum be larger than the third remaining side. This is the triangle inequality theorem.

I recommend you cutting out slips of paper with these side lengths and trying it out yourself. You'll find that a triangle cannot be formed. The 9.6 cm and the 11.6 cm sides will combine to form a straight line that is 21.2 cm, but a triangle won't form.

As another example of a triangle that can't be formed is a triangle with sides of 3 cm, 5 cm, and 8 cm. The 3 and 5 cm sides add to 3+5 = 8 cm, but this does not exceed the third side. The best we can do is form a straight line but that's not a triangle.

In short, zero triangles can be formed with the given side lengths of 9.6 cm, 11.6 cm, and 21.2 cm

3 0
3 years ago
11 halves divided by 7
Tamiku [17]

Answer:

\large\boxed{\dfrac{11}{14}}

Step-by-step explanation:

\dfrac{\frac{11}{2}}{7}=\dfrac{11}{2}\div7=\dfrac{11}{2}\div\dfrac{7}{1}=\dfrac{11}{2}\cdot\dfrac{1}{7}=\dfrac{(11)(1)}{(2)(7)}=\dfrac{11}{14}

4 0
3 years ago
Read 2 more answers
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