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3 years ago

Josh and Anthony have a lemonade stand.They charge $1 for 2 cups of

Mathematics

1 answer:

kap26 [50]3 years ago

7 0

No.Because 14/2=7 and 7*3=21 so $21 is the answer.

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Directions: Read, analyze, and choose the letter of the correct answer. Write your

svetoff [14.1K]

1) The normal room temperature is said to be about 20°C

2) 5 day is equivalent to 120 hr

3) 756 m³/s is equivalent 56000 L/s

4) It would take the snail 5 hours to crawl 75 m

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

1) The normal room temperature is said to be about 20°C

2) 1 day = 24 hr

5 day = 5 day * 24 hr per day = 120 hr

3) 1 m³ = 1000 L

756 m³/s = 56 m³/s * 1000 L/m³ = 56000 L/s

4) 1 m = 100 cm

75 m = 7500 cm

Time = 7500 / (25 cm/min) = 300 min = 5 hours

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0

2 years ago

Lucie drank 3/4 of a pint of bottled water. One serving of the water is 7/8 of a pint. How much of a serving did she drink.

attashe74 [19]

7/8
3/4
I'm order for them to have the same denominator you need to multiply so:
¾×2=6/8
So she drank 6/8 pints of water

8 0

3 years ago

Read 2 more answers

I’m not going on my own right path I

IrinaK [193]

Answer:

The answer is It is your opinion.

Step-by-step explanation:

thats your opinion .-.

7 0

3 years ago

Read 2 more answers

When the x is slove and you have to slove for the y i got how to do it but i don't know which one am i sloving for in the equati

harina [27]

Since x=8y, subsitute 8y for x in other equation

y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47
$\frac{11}{47}=y$
subsitute taht for y to find x

x=8y
$x=8(\frac{11}{47})$
$x=\frac{88}{47}$

$x=\frac{88}{47}$
$y=\frac{11}{47}$
in (x,y) form
(x,y)
$(\frac{88}{47},\frac{11}{47})$

3 0

3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago