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katrin [286]
3 years ago
12

If a line with a slope of -2 crosses the yaxis at (0,3) what is the equation of the line

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

y=-2x+3

Step-by-step explanation:

Notice that with the provided information they are given you not ust the slope of the line (-2), but also the y-intercept (the point where the line crosses the y-axis which happens when x=0).

So you can directly write the equation of the line in slope-intercept form [y=mx+b where "m" is the slope and "b" the y-value when x=0].

Such gives us:

y=-2x+3

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Bridgette had a whole pie. She ate 1/4 of the pie for a snack and ate another 25% of the pie for dessert. What fraction of the p
Kisachek [45]

Answer:

1/2

Step-by-step explanation:

Bridgette ate 1/4 of the pie, and 25% of the pie.

25% is converted to 1/4.

1/4 + 1/4 = 1/2.

1 - 1/2 = 1/2.

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3 years ago
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Bezzdna [24]

Answer:

4

Step-by-step explanation:

if 36.24 is divided by 90.6 can be 9.06

36.24÷9.06

4

or by other style

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according to the question

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3 years ago
Write a polynomial function, p(x) with degree 3 that has p(7)=0
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Answer:

p (x) = x^{3} - 21x^{2}+ 147x - 343

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}

Take a = x

        b = 7

Substitute in the identity we get

(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

p (x) = x^{3} - 21x^{2}+ 147x - 343

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