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uranmaximum [27]

3 years ago

6

Line z passes through the points (-6, 2) and (-1, -4), as shown below. Which of the following could be the equation of a line th

at is parallel to line z?
Select one or more:
A. y=−65x+10
B. y=65x−3
C. y=25x−1
D. y=x+4

Select one or more

1 answer:

WARRIOR [948]3 years ago

5 0

Answer:

D. y = x + 4

Explanation:

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Which role would result in a translation of two units left and three units up

VladimirAG [237]

The rule (x, y) ⇒ (x-2, y+3) will translate the way you want.

7 0

3 years ago

Wat is 20/24 as a decimal and a percent

Morgarella [4.7K]

$\frac{20}{24}=\frac{20:4}{24:4}=\frac{5}{6}\\\\\\\frac{5}{6}=0.8333...=0.8(3)\\\\\\\frac{5}{6}=\frac{5}{6}\cdot100\%=\frac{5}{3}\cdot50\%=\frac{250}{3}\%=83\frac{1}{3}\%$

7 0

3 years ago

Read 2 more answers

The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W

Alex_Xolod [135]

Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

$(x-a)^2+(y-b)^2=r^2$

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

$x^2+y^2+4x-12y+4=0$

Collect like terms and subtract 4 from both sides:

$\implies x^2+4x+y^2-12y=-4$

Complete the square for both variables by adding the square of half of the coefficient of $x$ and $y$ to both sides:

$\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2$

$\implies x^2+4x+4+y^2-12y+36=-4+4+36$

Factor both variables:

$\implies (x+2)^2+(y-6)^2=36$

Therefore:

center = (-2, 6)
radius = √36 = 6

7 0

2 years ago

Math Help Please??? Don't Answer If Unsure Please?

enot [183]

#1:
Solve:
-5/12 x 8/13 = -40/156
-40/156 can both be divided by 4: 40 ÷ 4 = 10 & 156 ÷ 4 = 39
Your final answer is: Option 2, -10/39

#2
Solve:
3/8 x (-3/6) you can first simplify 3/6 into 1/2 so-- 3/8 x (-1/2) = -3/16
Your answer is: -3/16

I've solved two of them for you, can you solve the rest on your own? (Reply if you need more answers)

5 0

3 years ago

Write as a product of two polynomials <br> a) 3a(2x–7)+5b(7–2x)<br> b) (x–y)^2–a(y–x)

saveliy_v [14]

Answer:

a) (3a-5b)(2x-7) or (-3a+5b)(7-2x)

b) (x-y)(x-y+a) or (y-x)(y-x-a)

Step-by-step explanation:

a) 3a(2x-7)+5b(-(-7+2x))

3a(2x-7)-5b(2x-7)

(3a-5b)(2x-7)

3a(-(-2x+7))+5b(7-2x)

-3a(7-2x)+5b(7-2x)

(-3a+5b)(7-2x)

b)(x-y)^2-a(-(-y+x))

(x-y)^2+a(x-y)

(x-y)(x-y+a)

(-1(-x+y))^2-a(y-x)

(1(y-x)^2-a(y-x)

(y-x)(y-x-a)

7 0

4 years ago