4 years ago

I have problems to found my answer, somebody can help me?

1 answer:

8 0

So final step to do is you square root the x^2 and square root the 4000 which will get you answer of x = 63.2455532034 which can be 63.2. Hope this help!!

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Given:

The expression is:

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

To find:

The value of the given expression when $x=64$ and $y=27$ .

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We have,

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

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