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Lostsunrise [7]
4 years ago
5

I have problems to found my answer, somebody can help me?

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
8 0
So final step to do is you square root the x^2 and square root the 4000 which will get you answer of x = 63.2455532034 which can be 63.2. Hope this help!!
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aleksley [76]

Given:

The expression is:

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

To find:

The value of the given expression when x=64 and y=27.

Solution:

We have,

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

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