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Genrish500 [490]
3 years ago
15

If c(x)=5/x-2 and d(x)=x+3, what is the domain of (cd)(x)

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0
I hope this helps you

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Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has
MrMuchimi

The answer to this question is C

8 0
3 years ago
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What is the slope of (-17,-11), (10,8)
poizon [28]
-11-8=-19
-17-10=-27

slope=19/27
6 0
3 years ago
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Given: ABCD parallelogram BK ⊥ AD , AB = 6, AK = 3 Find: m∠A, m∠B, m∠C, m∠D
Troyanec [42]

Answer: Angle A = 60°, angle B = 120°, angle C = 60°, angle D = 120°

Step-by-step explanation: Please refer to the attached diagram for further details.

The question has given the parallelogram ABCD as having side AB measuring 6 units, side AK measuring 3 units and line BK has been drawn perpendicular to line AD. This means line AK forms a right angle at the point where it meets line AD. From the information provided and the figure derived from that, we have right angled triangle ABK with the right angle at point K, line AB equals 6 units and line AK equals 3 units.

Using angle A as the reference angle, line AK is the opposite (side facing the reference angle), line AB is the hypotenuse (line facing the right angle) and line AK is the adjacent (side that lies between the right angle and the reference angle).

Hence, using the trigonometric ratios,

Cos A = adjacent/hypotenuse

Cos A = 3/6

Cos A = 0.5

Checking with the calculator, (that is second function of Cos 0.5)

A = 60

The opposite sides of a parallelogram are equal (that is line AD is parallel to line BC) and therefore opposite angles are equal (that is angle A is equal to angle C).

Similarly, angle B is equal to angle D. However, angles in a quadrilateral equals 360 degrees.

Therefore, angles in parallelogram ABCD is derived as;

A + B + C + D = 360

60 + B + 60 + D = 360

120 + B + D = 360

Subtract 120 from both sides of the equation

B + D = 240

Having known that angle B equals angle D, angles B and D is derived as each half of the value 240

Angle B = 240/2

Angle B = 120

and angle D = 120

Therefore, the angles are;

A = 60, B = 120, C = 60, D = 120

3 0
3 years ago
If Quadrilateral Q is a scaled copy of Quadrilateral P created with a scale factor of 3
Stolb23 [73]
I don't see a drawing of the quadrilaterals, so I don't know what the perimeter of quadrilateral P is. But whatever the perimeter of P is, Q will be 1/3 of that. Perimeter is a length, so even though it may pertain to a 2-dimensional object, it is still a 1-dimensional, linear measure. When two objects are similar (same shape, but scaled up or down by a scale factor), all corresponding linear measures have the same scale factor.

If you were asked about area or volume, that would be a different matter. In the case of area, you would square the scale factor, and in the case of volume, you would cube the scale factor.
7 0
3 years ago
Need Help!!! ASAP
RoseWind [281]

Answer:

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}

Step-by-step explanation:

The given probabilities are:

P(red)=\frac{2}{7}

P(blue)=\frac{3}{14}

Their sum is P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}

The probabilities that will complete the model should add up to \frac{1}{2} so that the sum of all probabilities is 1.

P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}

P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}

5 0
3 years ago
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