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2 years ago

Wolfrich lived in Portugal and Brazil for a total period of 14 months in order to learn Portuguese.

Mathematics

2 answers:

Allushta [10]2 years ago

4 0

We let...

x as the number of months he spent in Portugal

y as the number of months he spend in Brazil

From the problem, we can generate the following equations

x + y = 14

130x + 150y = 1920

Solving the equation gives us

x = 9 months in Portugal

y = 5 months in Brazil

quester [9]2 years ago

4 0

Answer: He lived in Portugal for 9 months and in Brazil for 5 months.

Step-by-step explanation:

Let the number of months he lived in Portugal be 'x'.

Let the number of months he lived in Brazil be 'y'.

Total number of months = 14

Average new words per month when he lived in Portugal = 130

New words in x months = 130x

Average new words per month when he lived in Brazil = 150

New words in y months = 150y

Total new words = 1920

So, our equation would be

$x+y=14-------(1)\\\\130x+150y=1920-------------(2)$

Let x = 14-y from equation 91).

Now, we put this value in equation (2).

$130(14-y)+150y=1920\\\\1820-130y+150y=1920\\\\1820+20y=1920\\\\20y=1920-1820\\\\20y=100\\\\y=5$

if y = 5

then, x= 14-5 = 9

Hence, he lived in Portugal for 9 months and in Brazil for 5 months.

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