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Levart [38]
2 years ago
9

I have an exam and I need you to help me

Mathematics
1 answer:
ivolga24 [154]2 years ago
6 0

Answer:

ok we are going to add 3 on both sides:

x/7 = 12

then we are going to multiply by 7 on both sides:

X = 84

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The value of 5x2 - 11x + 18 is<br> when x = 2.4 and<br> whenx = -3.
Virty [35]

Answer:

20.4

96

Step-by-step explanation:

The value of 5x² - 11x + 18 is

5(2.4)²-11(2.4) +18 = 5(5.76) -26.4+18

= 28.8 -26.4+18 = 20.4 (when x = 2.4)

and 5(-3)² -11(-3) +18 = 45+33+18 = 96

(when x = -3)

8 0
3 years ago
Read 2 more answers
Thuy wrote the system of equations. 24 x + 36 y = 72. Negative 16 x + 8 y = 80. If the second equation is multiplied by 3, what
Irina-Kira [14]

Answer:

multiply the first equation by 2

Step-by-step explanation:

24x + 36y = 72

-16x + 8y = 80

48x + 72y = 144

-48x + 24y = 240

96y = 384

y = 4

24x + 36(4) = 72

24x + 144 = 72

24x = -72

x = -3

(-3, 4)

7 0
3 years ago
Read 2 more answers
Who can help me number 5 please?
Blababa [14]
You have the right answer I think!!
8 0
3 years ago
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Please help!! The first correct answer that explains the steps gets brainliest
Sergio [31]

Answer:

All real numbers

Step-by-step explanation:

See attachment for step-by-step

7 0
2 years ago
The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri
VARVARA [1.3K]

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ AD^{2} + BD^{2} = AB^{2}

⇒AD^{2} =AB^{2} - BD^{2}

⇒AD^{2} =6^{2} -3^{2}

⇒AD^{2} =36 - 9 = 25

⇒AD = \sqrt{25}

⇒AD = 5 inches

6 0
3 years ago
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