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3 years ago

Find cot x if sin x cot x csc x = √2.

Mathematics

2 answers:

balandron [24]3 years ago

7 0

Answer:

The answer is (b) ⇒ cotx = √2

Step-by-step explanation:

∵ (sinx) (cotx) (cscx) = √2

∵ cotx = cosx/sinx

∵ cscx = 1/sinx

∴ (sinx)(cosx/sinx)(1/sinx) = √2

∴ cosx/sinx = √2

∴ cotx = √2

Free_Kalibri [48]3 years ago

5 0

Answer:

Choice B is correct.

Step-by-step explanation:

We have given sin x cot x csc x = √2.

We have to find cot x?

As we know that,

cot x= cos x/sinx eq (1)

and csc x = 1/sinx eq(2)

Put the eq(1) and eq(2) in the given function we get,

sin x ( cos x/sinx )(1/sinx) = √2.

cosx /sinx = √2.

cot x = √2 is the answer.

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