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Dmitriy789 [7]
3 years ago
7

What is the vertex form of the equation y=-x^2 + 12x-4 please show all steps!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

y=-1(x-6)^2+32

Step-by-step explanation:

vertex form: y=a(x-h) ^2+k

you have your equation in standard form : ax^2+bx+c

how to change it:

vertex x=(-b)/2(a)

x=-(12)/2(-1)

x=6

substitute x into original (standard-form) equation to find y

vertex y=-(6)^2+12(6)-4

y=32

substitute those values into your vertex (h,k) : (6,32)

y=-1(x-6)^2+32

hope this helps!! :)

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Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

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But the sample selected is too large and the probability of success is small.

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The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

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