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Dmitriy789 [7]
3 years ago
7

What is the vertex form of the equation y=-x^2 + 12x-4 please show all steps!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

y=-1(x-6)^2+32

Step-by-step explanation:

vertex form: y=a(x-h) ^2+k

you have your equation in standard form : ax^2+bx+c

how to change it:

vertex x=(-b)/2(a)

x=-(12)/2(-1)

x=6

substitute x into original (standard-form) equation to find y

vertex y=-(6)^2+12(6)-4

y=32

substitute those values into your vertex (h,k) : (6,32)

y=-1(x-6)^2+32

hope this helps!! :)

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