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aleksandr82 [10.1K]
3 years ago
7

50(1.05)t < 100 how much growth or decay

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0
50(1.05)t \ \textless \  100

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Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

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LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

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3 years ago
What is the answerrrrr to this
Alex_Xolod [135]
Area = 140

16 x 8 = 128

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A function may have two variables, x and y, and not be a linear function. For example, y = x² is not a linear function. The fact that it has two variables is not what makes it linear.

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