50(1.05)t < 100 how much growth or decay

Amira and Mandisa sell balloon animals at different stands on the boardwalk. They each use a constant number of balloons per ani

MAXImum [283]

Mandisa uses 5 balloons for each animal, this means that Mandisa uses more.

<h3>Linear equation</h3>

Linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Let y represent the number of balloons for x animals.

Amira uses 4 balloons for each animal.

For Mandisa, using the table using (20, 225) and (60, 25):

$slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{25-225}{60-20}=-5$

Therefore Mandisa uses 5 balloons for each animal, this means that Mandisa uses more.

Find out more on linear equation at: brainly.com/question/14323743

6 0

1 year ago

If B is the midpoint of AC, and AC=8x-20. Find BC<br> AB=3x-1<br> Show all work

exis [7]

First we know that:
AB+BC=AC
now , since B is the midpoint of AC, this means that AB=BC
therefore,
AB+BC=AC can also be written as
AB+AB=AC
3x-1+3x-1=8x-20
6x-2=8x-20
-2+20=8x-6x
18=2x
x=9

therefore:
AB=3(9)-1=27-1=26
AC=8(9)-20=52
BC=AB=26

6 0

3 years ago

Read 2 more answers

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

What is 5 *6?????........

andrey2020 [161]

Answer:

30

Step-by-step explanation:

7 0

3 years ago

Rupert buys a bicycle with a marked price of £ 12500.He gets a rebate of 10% on it. After getting

yarga [219]

Answer:

£ 12,150

Step-by-step explanation:

Marked price of bicycle = £ 12500

Rebate = 10%

Amount of rebate = 12500*10/100 = £1250

Rebated price = 12500 - 1250 = £ 11,250

Tax = 8%

Amount of tax = 11250*8/100 = £ 900

Total amount paid for bicycle = Rebated price + amount of tax

= £ 11,250 + £ 900

= £ 12,150

4 0

3 years ago