You need to specify the statement needed to use the equation. Thank you. I will then answer it if needed.
Answer: choice B) a35 = -118
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Explanation:
When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get
an = a1+d(n-1)
32 = a1+d(5-1)
32 = a1+4d
Solve for a1 by subtracting 4d from both sides
a1 = 32-4d
We'll plug this in later
Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula
an = a1+d(n-1)
7 = a1 + d(10-1)
7 = a1+9d
Now substitute in the equation in which we solved for a1
7 = a1+9d
7 = 32-4d+9d ... replace a1 with 32-4d
7 = 32+5d
5d = 7-32
5d = -25
d = -25/5
d = -5
This tells us that we subtract 5 from each term to get the next term.
Use this d value to find a1
a1 = 32-4d
a1 = 32-4*(-5)
a1 = 32+20
a1 = 52
The first term is 52
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The nth term formula is therefore
an = 52 + (-5)(n-1)
which simplifies to
an = -5n + 57
To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.
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Replace n with 35 to find the 35th term
an = -5n + 57
a35 = -5(35) + 57
a35 = -175 + 57
a35 = -118
Answer:
Step-by-step explanation:
Given the definite integral 
, we to evaluate it. Using integration by substitution method.
Let u = 1-2x⁵ ...1
du/dx = -10x⁴
dx = du/-10x⁴.... 2
Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;
![= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%5Cdfrac%7Bdu%7D%7Bu%5E5%7D%20%7D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%7Bu%5E%7B-5%7Ddu%20%7D%20%20%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5B%7B%5Cfrac%7Bu%5E%7B-5%2B1%7D%7D%7B-5%2B1%7D%5D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%28%7B%5Cfrac%7Bu%5E%7B-4%7D%7D%7B-4%7D%29%5C%5C%5C%5C)
substitute u = 1-2x⁵ into the result
Hence
Area of the entire rectangle 
Solution:
Area of the blue box = length × width
Area of the blue box 
Area of the pink box = length × width
Area of the pink box 
Area of the green box = length × width
Area of the green box 
Area of the orange box = length × width
Area of the orange box = 24
Total area of the rectangle 
Area of the entire rectangle
Answer: Treats are an essential part of positive reinforcement, rewards-based training, but you also need to be mindful to balance your dog’s treats with their overall daily calories. Give them too many treats and you won’t just spoil their appetite for actual meals, but you could also make your dog overweight and unhealthy.
Step-by-step explanation:
