Answer:
nth term = 18 - 3n
Step-by-step explanation:
nth term = a + (n - 1)d
a1 = 15
d = -3
nth term = a + (n - 1)d
= 15 + (n - 1)-3
= 15 + (-3n + 3)
= 15 - 3n + 3
= 18 - 3n
nth term = 18 - 3n
For instance, if you want to find the 10th term
nth term = 18 - 3n
10th term = 18 - 3(10)
= 18 - 30
= -12
10th term = -12
You have to use these facts:
1) The derivative of a sum is the sum of the derivatives
2) d[x^n] / dx = n x ^ (n - 1)
3) d [a(f(x) ] / dx = a d [f(x)] / dx
=> d [x^3 + 3x^2 + 5] / dx = d[x^3]/dx + 3d[x^2]/dx + 0
= 3x^2 + 6x
Answer: option D. 3x^2 + 6x
Answer:
I would assess what type of learner my student was by seeing which form of teaching they respond best to. I would try to cover all 7 types of learning by going through different examples. I would lead by explaining the concept and then start to work through at least 3 examples. I would then ask them to finish certain parts and eventually watch them work one out on their own. One of the key things I would make sure to do is personalize the learning experience. I would offer stories and situations that they may be able to relate to or remember when completing the problem.
1. =7
2.=19
Please let me know if you got it correct!
8+.9+.07 eight and ninety seven hundredths
