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3 years ago

Which expression is equal to (3x−5)(2x−7)?

Mathematics

2 answers:

olga2289 [7]3 years ago

8 0

(3x-5)(2x-7)
6x^2 - 21 x -10x +35
6x^2 -31x +35

The first one

DaniilM [7]3 years ago

4 0

Answer:

$6x^2-31x+35$

Step-by-step explanation:

Given expression,

$(3x-5)(2x-7)$

By using distributive property,

$(3x-5)(2x) - (3x - 5)(7)$

Again by distributive property,

$3x(2x) - 5(2x) - 3x(7) + 5(7)$

$6x^2 - 10x - 21x + 35$

$6x^2-31x+35$

Hence, FIRST option is correct.

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There are 15 books on a shelf. 9 of these books are new. The rest of them are used. what is the ratio of all books

Andrew [12]

Answer:

a)15:6 b)2:3

Step-by-step explanation:

No. of used books=15-9=6

a) 15:6

6:9

2:3

6 0

3 years ago

Does 4 = 2+2 it seem like I'm really dumb but, trust me this is really hard

igomit [66]

Answer:

Yes it does

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5 0

3 years ago

Read 2 more answers

Your sample size is 10 and your confidence is 90%. What is your t-score?

PilotLPTM [1.2K]

Answer:

if you want a t*-value for a 90% confidence interval when you have 9 degrees of freedom, go to the bottom of the table, find the column for 90%, and intersect it with the row for df = 9. This gives you a t*–value of 1.833 (rounded).

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

Solve the equation for the indicated variable (for c)<br><img src="https://tex.z-dn.net/?f=15%20%3D%20%20-%203%282c%20%2B%20d%29

11Alexandr11 [23.1K]

Answer:

c= -2.5-0.5d

Step-by-step explanation:

15=-3(2c+d)

15=-6c+-3d

15+3d=-6c

-2.5-0.5d=c

5 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

3 years ago