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iren [92.7K]
3 years ago
7

The height h is greater than 2.5 meters. Write an inequality for the word sentence

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer:

H > 2.5

Step-by-step explanation:

Greater = >

Lessthan = <

Equal = =

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Yesterday the snow was 2 feet deep in front of archies house. Today,the snow depth dropped to 1.6 feet because the day is so war
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Answer:

20%

Step-by-step explanation:

becuz 2×.2 = .4

subtract .4 from 2 and it's 1.6 and change the .2 to percentage

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Please help, if you don’t know, don’t answer.
Novosadov [1.4K]

Answer:

The answer is 1.

Step-by-step explanation:

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2 years ago
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Solve for x<br><br>O 5.5<br>O 6.5<br>O 7.5<br>O 8.5<br>​
Leni [432]

Answer:

x= 120

Step-by-step explanation:

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3 years ago
2+3(2x-5)-3(4z+6)-8 show me how to solve this problem
lakkis [162]

2+3(2x-5)-3(4z+6)-8

2+3(2x)+3(-5)-3(4z)-3(6)-8

2+6x-15-12z-18-8

2-15+6x-12z-18-8

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Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D
viva [34]

Answer:

\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C

Step-by-step explanation:

So we have the indefinite integral:

\int (\ln(x))^2dx

This is the same thing as:

=\int 1\cdot (\ln(x))^2dx

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}

Simplify:

du=\frac{2\ln(x)}{x}dx

And:

dv=(1)dx\\v=x

Therefore:

\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx

The x cancel:

=x\ln(x)^2-\int2\ln(x)dx

Move the 2 to the front:

=x\ln(x)^2-2\int\ln(x)dx

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

=x\ln(x)^2-2\int 1\cdot\ln(x)dx

Let u be ln(x) and let dv be (1)dx. Thus:

u=\ln(x)\\du=\frac{1}{x}dx

And:

dv=(1)dx\\v=x

So:

=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)

Simplify the integral:

=x\ln(x)^2-2(x\ln(x)-\int (1)dx)

Evaluate:

=x\ln(x)^2-2(x\ln(x)-x)

Now, we just have to simplify :)

Distribute the -2:

=x\ln(x)^2-2x\ln(x)+2x

And if preferred, we can factor out a x:

=x(\ln(x)^2-2\ln(x)+2)

And, of course, don't forget about the constant of integration!

=x(\ln(x)^2-2\ln(x)+2)+C

And we are done :)

8 0
3 years ago
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