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balu736 [363]
3 years ago
11

PLZ HELP WITH THIS QUESTION!

Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ± \sqrt{12^2-(4(-16)(-d))}) / - 32

 = ( - 12 ± \sqrt{144-64d}) / - 32

 = ( - 12 ± \sqrt{16(9-4d)}) / - 32

 = ( - 12 ± 4\sqrt{9-4d}) / - 32

 = \frac{-12}{-32} ± \frac{4}{-32}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{1}{8}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{\sqrt{9-4d} }{8} → D

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