Question

PLZ HELP WITH THIS QUESTION!

Answer 1

Answer:

D

Step-by-step explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ± $\sqrt{12^2-(4(-16)(-d))}$) / - 32

 = ( - 12 ± $\sqrt{144-64d}$) / - 32

 = ( - 12 ± $\sqrt{16(9-4d)}$) / - 32

 = ( - 12 ± 4$\sqrt{9-4d}$) / - 32

 = $\frac{-12}{-32}$ ± $\frac{4}{-32}$$\sqrt{9-4d}$

 = $\frac{3}{8}$ ± $\frac{1}{8}$$\sqrt{9-4d}$

 = $\frac{3}{8}$ ± $\frac{\sqrt{9-4d} }{8}$ → D