What is the value

yanalaym [24]

9514 1404 393

Answer:

(c) g(x) = 1/3·f(x)

Step-by-step explanation:

You can pick a point, such as the vertex at (2, -3) on f(x) and see which of the transformations gives you a point on the graph of g(x).

You will find that g(x) represents a vertical scaling by a factor of 1/3, so ...

g(x) = 1/3·f(x)

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The point (2, -3) on f(x) corresponds to the point (2, -1) on g(x).

5 0

3 years ago

Can you plz help me with this, because I don’t know how to do this and can u plz explain how to do it

Alecsey [184]

Answer:

Step-by-step explanation:

You can start this in may ways but let's start by isolating one of the parenthesis:

x (x² - 5) = - (x - 3)

x³ - 5x = -x + 3 (here I multiplied x for what's inside the parenthesis and the "minus" signal by the other parenthesis which was (x - 3))

x³ - 5x + x = 3

x³ -4x = 3

x³ -4x -3 = 0 (now this right here is a "depressed cubic equation" and it's one of the toughest sit of all time, so good luck with that, you might wanna take a look at this:

ytb/watch?v=rNDy2ZFvG1E

or maybe I'm doing something wrong and it's simpler than that, but whaterver...)

4 0

3 years ago

BRAINLIEST PLEASE ANSWER FAST What is 12.5% written as a decimal? 0.00125 0.125 1.25 12.5

r-ruslan [8.4K]

Your answer is .125.

4 0

3 years ago

Read 2 more answers

A cylinder shaped container has a radius of 30 cm and a height of 100 cm. A glass sphere with a redius of 12 cm is placed inside

Artemon [7]

Vcylinder-Vsphere=water

Vcylinder=hpir^2
Vsphere=(4/3)pir^3

given

cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness

sphereradius=12
Vsphere=(4/3)pi12^3=2304pi

cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm

last option is corrrect

4 0

3 years ago

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11