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erica [24]
3 years ago
10

What is the answer for - 4= 5+f

Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer:

Step-by-step explanation:

-4 = 5 + f....we want to isolate f, so subtract 5 from both sides

-4 - 5 = 5 - 5 + f

-9 = f <===

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$450 is deposited monthly for 11 years at 5% per year<br> FV=
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3) time = 11 years => number of periods = 11 * 12 = 132

4) Formula: FV = C * (1 + r) ^ (number of periods)

5) Calculation: FV = $450 * ( 1 + 0.00416)^(132) = $ 779.07

Answer: $ 779.07


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Calculate the density of a solid with the following data:
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2 years ago
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Me pueden ayudar en esta ecuación bicuadratica, porfaaa: 9p⁴=—12x²—6/9
Dominik [7]

Answer:

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Step-by-step explanation:

Pregunta correcta

¿Me pueden ayudar en esta ecuación biquadratica, por favor: 9x⁴ = —12x² - 6/9

Solución

9x⁴ = —12x² - 6/9

9x⁴ + 12x² + 6/9 = 0

multiplicar por 9

81x⁴ + 108x² + 6 = 0

Deje x² = y, entonces x⁴ = y²

81y² + 108y + 6 = 0

Resolviendo esta ecuación cuadrática

y = -0.0581 o y = -1.275

Recordemos, x² = y

x = ±√y

Si y = -0.0581

x = ± √(-0.0581) = ± 0.241i = 0.241i o -0.241i

Si y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i o -1.129i

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

¡¡¡Espero que esto ayude!!!

Correct Question

Can you help me in this biquadratic equation, please: 9x⁴ = —12x² — 6/9

Solution

9x⁴ = —12x² — 6/9

9x⁴ + 12x² + 6/9 = 0

multiply through by 9

81x⁴ + 108x² + 6 = 0

Let x² = y, then x⁴ = y²

81y² + 108y + 6 = 0

Solving this quadratic equation

y = -0.0581 or y = -1.275

Recall, x² = y

x = ±√y

If y = 0.0581

x = ±√(-0.0581) = ±0.241

If y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i or -1.129i

Hence x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Hope this Helps!!

5 0
3 years ago
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