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Irina-Kira [14]
3 years ago
5

What is the answer if you make m the subject y=Mx+c

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

y-c=Mx

M=(y-c)/x

M=y/x-c/x

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Svetach [21]

Answer:

3 cm base 4 cm height

Step-by-step explanation:

6 0
3 years ago
Simplify 0.2(-4x+5)-0.5(3x-11)
Gemiola [76]

Answer:

-2.3x + 6.5

Step-by-step explanation:

3 0
3 years ago
A student factors a^6 - 64 to (a^2-4)(a^4 + 4a^2+ 16).
Neko [114]

Answer:

Option (b) is correct.

The expression is equivalent, but the term is not completely factored.

Step-by-step explanation:

edge 2020

4 0
3 years ago
For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.
Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 120, \sigma = 8

Middle 60%

So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

Lower limit

X when Z has a pvalue of 0.20. So X when Z = -0.84

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X - 120}{8}

X - 120 = -0.84*8

X = 113.28

Upper limit

X when Z has a pvalue of 0.80. So X when Z = 0.84

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 120}{8}

X - 120 = 0.84*8

X = 126.72

4 0
3 years ago
Someone please help me find the value of x
Nady [450]

Hello,

5x² = 90/2

5x² = 45

x² = 45/5

x² = 9

x = √9 or x = -√9

x = 3 or x = -3

4 0
1 year ago
Read 2 more answers
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