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satela [25.4K]
3 years ago
15

Determine the equation of a line passing through the point (-4, 2) with a slope of 0.

Mathematics
1 answer:
gregori [183]3 years ago
3 0
Equation of a line y=mx+b

plug in the values that you know: 2=0*-4+b then solve for be
b=2

Plug in b and the slope(m): y=0*x+2

answer: y=2
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Helppppp plzzzzz nowww
MatroZZZ [7]

Answer:

52°

Step-by-step explanation:

A and D correspond to each other and we know A is 52°, so D is 52°.

5 0
3 years ago
A wooden artifact from an ancient tomb contains 70% of the carbon-14 that is present in living trees. How long ago was the artif
noname [10]
So the question ask to determine how long that the wooden artifact found in an ancient tombs and contains 70% of the carbon-14 was made, and base on the fact and the given data about the said artifact, the possible answer would be that the the artifact is 2948 years old. I hope you are satisfied with my answer 
3 0
3 years ago
?<br> Which number is equivalent to 5 x 10+4 x 1+8 x 16 + 6 x 100 +1x<br> 1,000
Elan Coil [88]

Answer:

1,854

Step-by-step explanation:

MULTIPLY FIRST:

5 x 10 = 50

4 x 1 = 4

8 x 16 = 128

6 x 100 = 600

1 x 1000 = 1000

ADD:

50 + 4 + 128 + 600 + 1000 = 1,854

6 0
4 years ago
Read 2 more answers
You are traveling down a country road at a rate of 95 feet/sec when you see a large cow 300 feet in front of you and directly in
emmainna [20.7K]

Answer:

1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.

2) See attached picture.

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

Step-by-step explanation:

1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:

j(t)=95t-9t^2

j'(t)=95-18t

and we set the first derivative equal to zero so we get:

95-18t=0

and solve for t

-18t=-95

t=\frac{95}{18}

t=5.28s

so now we calculate the position of the car after 5.28 seconds, so we get:

j(5.28)=95(5.28)-9(5.28)^{2}

j(5.28)=250.69ft

so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.

2) For answer 2 I take the second derivative of the function so I get:

j(t)=95t-9t^{2}

j'(t)=95-18t

j"(t)=-18

and then we graph them. (See attached picture)

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3)  yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

5 0
3 years ago
IQ scores for adults age 20 to 34 years are normally distributed according to N(120, 20). In what range does the middle 68% of p
Ilya [14]

The required interval of the given normal distribution using the empirical rule is <u>[100, 140]</u>.

The empirical rule formula (also known as a 68 95 99 rule formula) uses data from a normal distribution to determine the first, second, and third standard deviations, which, respectively, differ from the mean value by 68%, 95%, and 99%. Additionally, it shows that 99.9% of the data fall inside the third standard deviation range (either above or below the mean value). The empirical rule formula is described below with cases that have been resolved.

In the question, we are given that IQ scores for adults aged 20 to 34 years are normally distributed according to N(120, 20), and are asked for the range in which the middle 68% of people in this group score on the test.

N(120, 20) signifies a normal distribution with mean, μ = 120, and the standard deviation, σ = 20.

By the empirical formula, 68% of the data lies within one standard deviation from the mean.

Thus, the required interval is [μ - σ, μ + σ] = [120 - 20, 120 + 20] = [100, 140].

Learn more about the empirical rule at

brainly.com/question/10093236

#SPJ4

6 0
1 year ago
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