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motikmotik
3 years ago
14

Solve for substitution of Y=x-1 and 2x-y=0

Mathematics
2 answers:
daser333 [38]3 years ago
8 0
Step One: Plug in (x-1) for y in 2x-y = 0
2x-(x-1)=0
Step Two: Distribute the negative
<u />2x -x -(-1)=0 \\ 2x-x+1=0
Step Three: Add like terms on one side of the equation
x + 1=0
Step Four: Subtract 1 from both sides
x+1-1=0-1 \\ x = -1
Step Five: Plug x into one original equation (I chose y=x-1 but you can do either one)
y=x-1 \\ y=-1-1 \\ y=-2
That's the answer to the problem, x = -1, y = -2 (-1,-2)!
Hope this helps!
satela [25.4K]3 years ago
8 0

<span>Step One: Plug in (x-1) for y in 2x-y = 0

Step Two: Distribute the negative
<u />
Step Three: Add like terms on one side of the equation

Step Four: Subtract 1 from both sides

Step Five: Plug x into one original equation (I chose y=x-1 but you can do either one)

That's the answer to the problem, x = -1, y = -2 (-1,-2)!
Hope this helps!</span>
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Step-by-step explanation:

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How do u write 20,484,163 in expanded form
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8 0
3 years ago
A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4
skad [1K]

Answer:

a) \bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

b) The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And if we replace we got:

\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

3 0
4 years ago
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