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motikmotik
3 years ago
14

Solve for substitution of Y=x-1 and 2x-y=0

Mathematics
2 answers:
daser333 [38]3 years ago
8 0
Step One: Plug in (x-1) for y in 2x-y = 0
2x-(x-1)=0
Step Two: Distribute the negative
<u />2x -x -(-1)=0 \\ 2x-x+1=0
Step Three: Add like terms on one side of the equation
x + 1=0
Step Four: Subtract 1 from both sides
x+1-1=0-1 \\ x = -1
Step Five: Plug x into one original equation (I chose y=x-1 but you can do either one)
y=x-1 \\ y=-1-1 \\ y=-2
That's the answer to the problem, x = -1, y = -2 (-1,-2)!
Hope this helps!
satela [25.4K]3 years ago
8 0

<span>Step One: Plug in (x-1) for y in 2x-y = 0

Step Two: Distribute the negative
<u />
Step Three: Add like terms on one side of the equation

Step Four: Subtract 1 from both sides

Step Five: Plug x into one original equation (I chose y=x-1 but you can do either one)

That's the answer to the problem, x = -1, y = -2 (-1,-2)!
Hope this helps!</span>
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chubhunter [2.5K]

Answer:

We conclude that

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Step-by-step explanation:

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Find the measure of each of the two angles.

<u>Important Points about linear pair:</u>

  • We know that when two lines meet or intersect, we get a linear pair of angles.
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As

<1 and <2 form a linear pair

m∠1 = 4m∠2

In other words, angle 1 is 4 times the measure of angle ∠2.

Let the angle ∠1 be = x

As the angle 1 is 4 times the measure of angle ∠2, so

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As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so

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